Author Topic: Resonant Cavity - The truth about amp loading! - Discussion  (Read 3498 times)

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Resonant Cavity - The truth about amp loading! - Discussion
« on: January 01, 2016, 23:53:49 pm »
Some people saying that stan states that per VIC unit from the dune buggy the amp draw at resonance or out of it will be few milliamps.
That is not true and lets discuss that in fair way.

Here is some start point:

Look into voltage amplitude control, There is an adjustable linear voltage regulator that can handle about 1 or 1.5 amp ALONE, right?
Why did Stan put it coupled with 2n3055 transistor?

The answer is easy:
To work ABOVE this load (from 2 to about 6 Amps at maximum).

Lets talk about it and make this forum back to live again.

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Re: Resonant Cavity - The truth about amp loading! - Discussion
« Reply #1 on: January 02, 2016, 01:39:30 am »
The simple fact is, amps are going to jerk the water molecules back and forth.  Is this what Stan was doing?  If he used a rotating electric field, as a particle accelerator, then amps would play a role.  The moving water molecules would dissociate on impact with an electrode or other molecule.  But if the molecules are to remain stationary, so that they can be stretched apart with potential pulses only, then amps would have to be minimized.  Was he doing one thing and saying something else?

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Re: Resonant Cavity - The truth about amp loading! - Discussion
« Reply #2 on: January 02, 2016, 02:34:24 am »
There is no proof or evidence about this.
No one tested the VIC and cell from the dune buggy.

If it draws almost nothing what can explain the lm317 coupled to 2n3055 in each VIC card for the amplitude regulation?

Thats a fact and my point of view.

To get high voltage (if there is any used) it requires power (Pin=Pout) -  no magic.



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Re: Resonant Cavity - The truth about amp loading! - Discussion
« Reply #3 on: January 02, 2016, 04:00:08 am »
To get high voltage (if there is any used) it requires power (Pin=Pout) -  no magic.

Then that's your answer.

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Re: Resonant Cavity - The truth about amp loading! - Discussion
« Reply #4 on: January 02, 2016, 11:51:36 am »
Amps are needed to produce the magnetic field which powers the transformer.  Minimal current at the cell doesn't mean there is no draw at the input to the circuit.  The key is to get rid of the amps in the output.  A resonant choke will only pass current at its resonant frequency.  With even a little detuning, the amps will quickly fall off and diminish.  A choke which completely blocks the current will still pass a high voltage longitudinal pulse.  (According to Farnsworth.)  What we should be looking at is what kind of energy is being applied to the cell?

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Re: Resonant Cavity - The truth about amp loading! - Discussion
« Reply #5 on: January 02, 2016, 14:49:06 pm »
mAN THE QUESTION IS TO A CAPACITOR TO GET CHARGED YOU MUST DO WHAT? force? work right?

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Re: Resonant Cavity - The truth about amp loading! - Discussion
« Reply #6 on: January 02, 2016, 14:54:09 pm »
Yes your point of view is correct, but i belive that minimum current Stan stated is across the cell, even at 0.025A over  2KV will draw 50W
that represent a primary load of  4.17A @ 12V.

But some people used to say that this load is as primary and this is clear on the patent : Load across the cell.

Stan stated it even in new zeland house meeting video.

39:22 to 40:00 You can hear it from Stan's words:




The pictures and the data collected by Dynodon is very precious! Thanks to him again and again!

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Re: Resonant Cavity - The truth about amp loading! - Discussion
« Reply #7 on: January 02, 2016, 14:55:40 pm »
See the video and tell me what you think.