A green and clean environment is a human right!
General => General Discussion => Topic started by: timeshell on August 21, 2022, 15:53:08 pm
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Hi all. Been a while.
Here's a basic question to think about...
What REALLY is the water fuel cell?
Answers please ...
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Let me go a little further with the first question...
It's not a basic capacitor. How would you draw it as a schematic...
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Really? Nobody wants to take a stab at this? 😂
Come on guys, I'm trying to make a point...
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Doesn't the WFC behave sort of like this?
What is this?
This is the target frequency people.
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I dont think so.
2 plates spaced by a water dielectric behaves like a resistor. You can frequency sweep it from DC to 1 GHz and see no changes in voltage/current/gas generation, thats not the behaviour of a capacitor used in a LC tuned circuit. Stan even says that in the WFC memo, that the water will become part of the circuit in form of resistance.
When you energize this kind of reactor, the voltage that develops across it, is the product of RxI, nothing more, and you get pure electrolysis only.
All you can do is increase the reactor impedance, to get a higher V/I ratio, and therefore rip the water molecule with less current. You cannot reach resonance with an inductor in series with a resistor.
In my opinion, this voltage ripping the molecule apart, only works in a very small scale, thats why he moved to the injectors.
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I feel like timeshell is correct... You have resistance and reactance in the cell this is why it will never behave like a conventional LC tank circuit.. Its over damped cause of the existence of R in the cell.. Makes it s parallel RC circuit of sorts..
But in this case the R exist in the same space as C. they are in the same component..
When I have done test with a lcz meter on a cell it DOES NOT behave like you would want it to match the idea of parallel RC.. Its actually inversed.. You would think that as freq increased the phase angle would increase and the cell would pass more power into the reactive component and less power into the resistive component of the cell.. But based on the lcz meter this is opposite.. It shows the phase angle increases as you lower the frequency. The capacitance value of the cell increases a lot as you lower the frequency as well.. which is not normal for a pure capacitor to do.
A pure capacitor having a pure dielectric would maintain close tolerance of capacitance reading at all test freqs. Spring water does not.
The only thoughts I can come up with this situation is that this parallel RC has another feature that differs from a conventional parallel RC circuit. It is a liquid dielectric with electrolytes. This allows for things like a hemholtz layer to form on the electrode... A form of electrochemical storage of power with the ionic contaminates occurs they refer to as pseudo capacitance.
Pseudo capacitance may be what the LCZ meter is presenting as I lowered the test frequency.. The lower frequency would allow more time for ion collection to occur at the electrodes during the test. also a false appearance of increased capacitance.
A water cell has a poor power factor.. There are losses in it from resistance but if there is a way to produce a great amount of fuel with a poor power factor that's ok because this capacitor is not just a capacitor for storing and processing power in a circuit. Its a material processor as well. Its expected to have some losses and consume energy in the production of fuel.
https://en.wikipedia.org/wiki/Pseudocapacitor
https://en.wikipedia.org/wiki/Double_layer_(surface_science)
https://www.youtube.com/watch?v=Z9nXVxm_Egc
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Just sweep your cell from DC to 1GHz monitoring current and voltage, absolutely no phase shift between them, using a power sweep, 100V DC at least. It`s a resistor. You`ll never get "pure voltage potential" in a resistor to split the water. And dont forget to use a carbon resistor as a current shunt for current measurement, wire resistors give false readings.
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just my two cents on this technology is that the wfc always returns some voltage / current, when you switch the power off.
It acts a bit as a capacitor.
If you can pick up that charge then your second pulse will be maximum twice the voltage as then your powersupply is giving...
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but maybe we are all wrong here and we should listen to good old Bob Boyce and setup a pulsing system that collects power from the aether
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Well, I made this test over and over. From DC to 1GHz, it acts as a resistor, with voltage in the cell beign Rcell x Icell. No voltage/current returning when switching off signal, only resistance (voltage and current are linear functions). The cell can hold aprox. 1,5[V] before electrolysis begin and thats all.
As Stan said:
Water now becomes part of the Voltage Intensifier Circuit in the form of "resistance" between electrical ground and pulsefrequency positive-potential ... helping to prevent electron flow within the pulsing circuit (AA) of Figure 1-1.
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Hello uziao.
We can see the cell behaving like a capacitor below the 2V.
Get a milliamp meter, and an good precision adjustable power supply.
Rise the voltage like 0,25 or 0.5 at a time, you will see the milliamps climb up as you rise the voltage and come down again, until you reach the 2v marks.
Also, if you use a signal generator and an oscilloscope across the cell, you can observe one thing:
You will get a pure dc voltage below 2v threshold, above that, you will have the signal you put in (eg. square wave) and it behaves like a resistor.
If we want to get further on this technology we need to forget about the patents and other stuff and learn by experimenting and observation, Meyer did not gave everything in a silver plate to everybody out there, and don't assume everything he says as the full truth, he was not that stupid to give his work for free.
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Yeah, if you do not have enough voltage to start electrolysis, you have no current flowing, whats the point? How does this relate to high voltage water dissociation? All my tests were made with high voltage and the cell behaves always like a resistor. If you restrict the current, using inductors, you`ll have less voltage in the cell, and therefore less gas, because as I said, Vcell = Rcell X Icell.
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The point is to prove that water behave as dielectric, but under that threshold voltage.
We are on this for years over this forum.
I dont know how many knowledge do yo have about Meyer, but if you are new to this, I suggest you to read the http://www.globalkast.com/docs/International-Independent-Test-Evaluation-Report.pdf (http://www.globalkast.com/docs/International-Independent-Test-Evaluation-Report.pdf) and do some math about the production and power.
As a lot of people had seen, there is a lot of bad figures on Meyer numbers, even in this document.
My intention is only save people some time and frustration about this, but everybody has the legitime right to desagree, but the numbers don't lie.
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Yeah, if you do not have enough voltage to start electrolysis, you have no current flowing
You do have current flow without electrolysis, until the "capacitor" charges up.
You can try it with a big cell and you can observe it easily. ;)
If it looks to you irrelevant, it is up to you, but there is more interesting things happening in the cell that some people do not talk about or is just ignoring.
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Yeah, if you do not have enough voltage to start electrolysis, you have no current flowing
You do have current flow without electrolysis, until the "capacitor" charges up.
You can try it with a big cell and you can observe it easily. ;)
If it looks to you irrelevant, it is up to you, but there is more interesting things happening in the cell that some people do not talk about or is just ignoring.
Is called displacement current, it is the charge that builds up before the conduction current kicks in.
I'm really confused right now, are we trying to replicate Meyers high voltage, high frequency aparatus, or are we trying to prove some low voltage stuff that has nothing to do with meyer? If you make your cell bigger, you'll have less resistance between the plates and more current will flow for the same voltage. Thats why he moved to the high resistance injectors, he even needed stainless steel enameled wire with high resistance in order to match the transformer to the injectors. What im trying to say, is that the only way to achieve high voltage, with low current in a water bath, is to make the electrodes very small. The cells impedance will never change, even when in resonance, because above 2v, it is a resistor. You cant restrict current in a resistor, you cant violate ohms law, you cant make voltage go up and amps go down in a resistor, the only way is if you make the resistance high enough, making it small enough.
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Uziao , I agree to desagree...
If you want to know this technology, you should understand any aspect of it.
The point I made about the capacitor under 2V was found experimenting.
About the impedance of the cell never change, it is not completely true.
If you really want to know more about this, search over this forum, or do your homework... :-\
Cheers.
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he even needed stainless steel enameled wire with high resistance in order to match the transformer to the injectors
This is not the only important property of this wire (430fr), and most people are ignoring something VERY important about that.
Remember, when you use resistive element, the power is dissipated on it...
Calculate the power loss on that resistance and tell me what do you see...
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he even needed stainless steel enameled wire with high resistance in order to match the transformer to the injectors
This is not the only important property of this wire (430fr), and most people are ignoring something VERY important about that.
Remember, when you use resistive element, the power is dissipated on it...
Calculate the power loss on that resistance and tell me what do you see...
You are right, it takes little power to convert some microdroplets of water into hydrogen, thats the beauty of the small injectors, and, according to stan, you'll end up ionizing the hydrogen as a "side effect" after the water dissociation. The injector electrode resistance needs to be equal to the coils resistance to ensure max power transfer. When you make the electrodes small, the resistance goes up, it means that the ratio V/I increases and you have more voltage than current.
You cant do the same with some 4 inch long cells, it takes much more power and much more current, mine has about 100ohms resistance. If you put 10kV in a 100ohms resistance, you'll end up with 100A. If you put 10kV in a 10kohms resistance, you'll end up with 1A.
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Well, I made this test over and over. From DC to 1GHz, it acts as a resistor, with voltage in the cell beign Rcell x Icell. No voltage/current returning when switching off signal, only resistance (voltage and current are linear functions). The cell can hold aprox. 1,5[V] before electrolysis begin and thats all.
As Stan said:
Water now becomes part of the Voltage Intensifier Circuit in the form of "resistance" between electrical ground and pulsefrequency positive-potential ... helping to prevent electron flow within the pulsing circuit (AA) of Figure 1-1.
You are correct Uziao
IF the chokes are made so that the electrons can not flow at a high rate through the positive choke and hit the forward diode, but rather get trapped in the choke, the positive tube will polarize.(just like Stan states). It also has to be on a floating ground so the current is limited. (isolation xfmr).
The reason your not getting more than 1.5v on the cell is because the electrons are whizzing right through the positive plate into the choke so fast a positive charge can not build up on the plate.
For example, The gap of the cell and the conductivity of the water determine how much voltage will build up on the cell. A .060 gap with rain water will start making gas somewhere around 24volts. Tap water would be around 14v. (straight across the cell) A tighter gap would also give less voltage. This is all dependent on how the chokes are made.
Go to 1:04 in the video
In my tests, with a .060 gap and rain water, The pulse train would charge up to the 24v level. Meaning the whole pulse train floats positive. From there with continued pulsing, it would step up to 90v. When pulsing is stopped. The pulse train will drop fast to the 24v level then very slowly down. (the gas output is still a function of the current in the circuit)
So, once the threshold level is met we get electron crossover from ground and electrolysis. If this was not the case the cell would keep charging higher and higher (like he states).
He does a lot of mixing different processes with his patents etc to cover all the bases for patent infringement. What he describes applies to water vapor in the water injector because it is in a different state. If this is applied to that, then it all makes sense. The voltage and resistance go sky high. However, it is also possible to do it on a small scale like I did, but your not going to be making boat loads of gas.
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Well, I made this test over and over. From DC to 1GHz, it acts as a resistor, with voltage in the cell beign Rcell x Icell. No voltage/current returning when switching off signal, only resistance (voltage and current are linear functions). The cell can hold aprox. 1,5[V] before electrolysis begin and thats all.
As Stan said:
Water now becomes part of the Voltage Intensifier Circuit in the form of "resistance" between electrical ground and pulsefrequency positive-potential ... helping to prevent electron flow within the pulsing circuit (AA) of Figure 1-1.
You are correct Uziao
IF the chokes are made so that the electrons can not flow at a high rate through the positive choke and hit the forward diode, but rather get trapped in the choke, the positive tube will polarize.(just like Stan states). It also has to be on a floating ground so the current is limited. (isolation xfmr).
The reason your not getting more than 1.5v on the cell is because the electrons are whizzing right through the positive plate into the choke so fast a positive charge can not build up on the plate.
For example, The gap of the cell and the conductivity of the water determine how much voltage will build up on the cell. A .060 gap with rain water will start making gas somewhere around 24volts. Tap water would be around 14v. (straight across the cell) A tighter gap would also give less voltage. This is all dependent on how the chokes are made.
Go to 1:04 in the video
In my tests, with a .060 gap and rain water, The pulse train would charge up to the 24v level. Meaning the whole pulse train floats positive. From there with continued pulsing, it would step up to 90v. When pulsing is stopped. The pulse train will drop fast to the 24v level then very slowly down. (the gas output is still a function of the current in the circuit)
So, once the threshold level is met we get electron crossover from ground and electrolysis. If this was not the case the cell would keep charging higher and higher (like he states).
He does a lot of mixing different processes with his patents etc to cover all the bases for patent infringement. What he describes applies to water vapor in the water injector because it is in a different state. If this is applied to that, then it all makes sense. The voltage and resistance go sky high. However, it is also possible to do it on a small scale like I did, but your not going to be making boat loads of gas.
When you change the water type and cell gap, you only change the resistance of the cell, therefore you need more voltage to push the same current thru it, if you put distilled water the 1.5v can climb up to 50v before electrolysis start. You'll always have the voltage in phase with current, never high voltage only polarization, you cant change it with chokes, resonance or whatsoever. When you polarize a resistor, current flows thru it. The real capacitor has a dielectric that does not allow DC current across it, the water capactor does not have this, therefore DC current will always flow thru it, like a resistor. The water capactior will never show a phase shift between current and voltage, even in its "polarization" phase. The result is both in phase, always, as in a resistor.
Measure your current with a carbon resistor, along with the voltage across the cell, and post the results to us. I did this many times, and the voltage waveform is identical to the current, V=R.I, linear function, more voltage = more current and never the opposite, thats impossible in a resistor, no matter how the chokes are. When you have bigger chokes, you have low voltage in the cell because they restrict all the current in the circuit. I have a Tektronix TPS 2014, so I can see both current and voltage directly in the same circuit without the need of isolation, this way the measurements are more accurate.
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Yes, the current and voltage are always in phase. I just made it work the way he said it was supposed to. That's what I found. I kind of thought of it as a resistive inductor because the metal tubes polarized and stored a charge. I was able to disconnect the circuit and put a LED across the cell and keep it lit for about 20 seconds as the charge bled off the cell. That is only the tubes not the circuit.Stan talks about changing the structure of the metal.
That's not how I made the chokes.
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Yes, the current and voltage are always in phase. I just made it work the way he said it was supposed to. That's what I found. I kind of thought of it as a resistive inductor because the metal tubes polarized and stored a charge. I was able to disconnect the circuit and put a LED across the cell and keep it lit for about 20 seconds as the charge bled off the cell. That is only the tubes not the circuit.Stan talks about changing the structure of the metal.
That's not how I made the chokes.
You'll never polarize and crack water with current and voltage in phase, you'll only do electrolysis, when you increase the voltage, more and more current will flow. I put my "water capacitor" inside a resonance lc circuit, with 300V input, my pulse peaks at 1000V at resonance, I have much gas, so much that it pops out of the top of the container, but the current peaks are insane, pure electrolysis. It could be a more efficient type, but nothing about low current and high voltage.
If you want to keep the LED on for longer, you need to replace the plates material. Instead of two plates of SS, use one SS and other made of aluminum and change water for sulfuric acid. This is a well known technology, called "the battery".
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Something interesting happens when you apply voltage across a "water capacitor":
As you rise the voltage, without restricting it, the resistance drops, in a non-linear behaviour, Andija Puharich call it a non-linear load.
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This is my water cell. Seems to act like a capacitor to me.
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This is my water cell. Seems to act like a capacitor to me.
If you check the current, it will have the same waveform, it wont be a capacitor current waveform.
https://industrial.panasonic.com/content/data/common/ss-files/tech14-06_ww.png (https://industrial.panasonic.com/content/data/common/ss-files/tech14-06_ww.png)
Your waveform is only a result of Icell x Rcell. It looks like a charging capacitor because the inductors are lagging the current, and the current, multiplied by the resistance of the cell, gives you this waveform. But this waveform is only the inductor current waveform.
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LC transient response to DC is identical to the LR circuit.
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LC transient response to DC is identical to the LR circuit.
Its LR and RC, not LC.
Yeah the waveforms are similar, but current and voltage are inverted in the components. Capacitor lags voltage peaks current, inductor lags current peaks voltage.
YOu have an LR circuit, your cell voltage has the same waveform of a resistor voltage in series with an inductor.
You have exactly the blue curve in your first pic, the inductor current waveform, multiplied by the resistance of your resistor (water capacitor), gives you the "water capacitor" waveform.
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Not my latest but you get an idea.
Yellow: input
Blue: voltage on the cell.
The current is identical to voltage, pure electrolysis. This waveform is just the result of the current being modulated by the inductors (inductor modulator as said by Stan), multiplied by the resistance of the cell.
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A coil with zero resistance has infinite time to get maximum current for any applied voltage..
A coil with infinite resistance will have no current for any applied voltage... such coil does not exist however when the resistance is bigger than the dielectric coeficient the coil can behave as kind of a capacitor...
Stan makes citation tay he han patent on dielectric used to cause dissociation by colision
Eccles uses plastic to kind of achieve the same...
Stan says that no electron is ejected from water during the polarization... that is only possible below 1,24 v since its the voltage that depending on the material the water start to ionize and give up electrons to the electrode...
The concept of a pressed or stretched spring trying to oscillate... only the middle is free to oscillate
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Yeah, if you do not have enough voltage to start electrolysis, you have no current flowing
You do have current flow without electrolysis, until the "capacitor" charges up.
You can try it with a big cell and you can observe it easily. ;)
If it looks to you irrelevant, it is up to you, but there is more interesting things happening in the cell that some people do not talk about or is just ignoring.
Is called displacement current, it is the charge that builds up before the conduction current kicks in.
I'm really confused right now, are we trying to replicate Meyers high voltage, high frequency aparatus, or are we trying to prove some low voltage stuff that has nothing to do with meyer? If you make your cell bigger, you'll have less resistance between the plates and more current will flow for the same voltage. Thats why he moved to the high resistance injectors, he even needed stainless steel enameled wire with high resistance in order to match the transformer to the injectors. What im trying to say, is that the only way to achieve high voltage, with low current in a water bath, is to make the electrodes very small. The cells impedance will never change, even when in resonance, because above 2v, it is a resistor. You cant restrict current in a resistor, you cant violate ohms law, you cant make voltage go up and amps go down in a resistor, the only way is if you make the resistance high enough, making it small enough.
I like your way of thinking...idk Y after reading ur post Google decided to show me why a ceiling fan needs a capacitor lol ...anyways good luck hope to read more from ya :)
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https://youtu.be/onMzxMtTSdA
Look familiar?
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This is my water cell. Seems to act like a capacitor to me.
Gapping the core in your chokes will also help allow those pulses to have a wider amplitude swing.
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90v peak to peak?
How about the amps?
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Amperage is absolute minimum with such short periods. <200mA max, but as low as 5-10mA in certain cases which are inversely proportionate with gate offtime.
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Amperage is absolute minimum with such short periods. <200mA max, but as low as 5-10mA in certain cases which are inversely proportionate with gate offtime.
Is this peak? RMS? How are you measuring it?
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I believe you want to charge up the cell using voltage LESS THAN what is needed to achieve electrolysis. This is the only way to get a charge on the cell. Once the cell is charged, only then should the high voltage pulse hit it to liberate the charge. If you keep hitting it with +electrolysis voltage, that's all you're going to get. The coils should be opposing reach other and tuned appropriately. This limits it to charging as the fields cancel each other out. If tuned right, this also helps keep the initial voltage low. This would start the process. Once you get the cell charged to where you want it, then up the voltage and retune resonance to up the voltage so high spikes crack all the water that has already been charged below electrolysis voltage.
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Yes, I agree. Duty Cycle Pulses were Stan's method of controlling this sustained polarization and bursting amplitudes.
Also, most people never realize the great inhibition on tuning pulses and core saturation, that a percentage based duty cycle adjustment causes. All your signal generators are flawed, making it nearly impossible to tune replications of Stan's circuits due to all the differences in the VIC Matrix caused by parasitics and ideal vs real component behaviors.
Only having independent width and spacing control circumvents this flaw. I'm writing an article on my research on this subject that I will share sometime soon. :)
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I believe you want to charge up the cell using voltage LESS THAN what is needed to achieve electrolysis. This is the only way to get a charge on the cell. Once the cell is charged, only then should the high voltage pulse hit it to liberate the charge. If you keep hitting it with +electrolysis voltage, that's all you're going to get. The coils should be opposing reach other and tuned appropriately. This limits it to charging as the fields cancel each other out. If tuned right, this also helps keep the initial voltage low. This would start the process. Once you get the cell charged to where you want it, then up the voltage and retune resonance to up the voltage so high spikes crack all the water that has already been charged below electrolysis voltage.
I have this belief too.. somehow I believe when Stan talk about the cell working like a short circuit is about making the minimum required voltage become zero at some point and even reversed!
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Yes, I agree. Duty Cycle Pulses were Stan's method of controlling this sustained polarization and bursting amplitudes.
Also, most people never realize the great inhibition on tuning pulses and core saturation, that a percentage based duty cycle adjustment causes. All your signal generators are flawed, making it nearly impossible to tune replications of Stan's circuits due to all the differences in the VIC Matrix caused by parasitics and ideal vs real component behaviors.
Only having independent width and spacing control circumvents this flaw. I'm writing an article on my research on this subject that I will share sometime soon. :)
What you mean? With flawed signal generators? What would make it impossible to tune? To have mark space is not hard… even the pll can be made to have variable duty cycle… the fracture cell also Is some very good for the abilities
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Yes, I agree. Duty Cycle Pulses were Stan's method of controlling this sustained polarization and bursting amplitudes.
Also, most people never realize the great inhibition on tuning pulses and core saturation, that a percentage based duty cycle adjustment causes. All your signal generators are flawed, making it nearly impossible to tune replications of Stan's circuits due to all the differences in the VIC Matrix caused by parasitics and ideal vs real component behaviors.
Only having independent width and spacing control circumvents this flaw. I'm writing an article on my research on this subject that I will share sometime soon. :)
I dont know. Stan has the 7490 I.C in the circuit. this chip divides frequency and outputs a 50-50 duty cycle, so he never adjusted duty cycle in the high frequency signal, he only adjusts the gate (low freq signal) pulse and width. In the images where the primary signal is round and stretched is the result of transformer action only, not electronics.
So far, I never saw someone increasing the voltage at the cell with decreasing current at the same time. More voltage = morre current, always, thats ohms law. If you apply a HV pulse, current will flow based on the cell resistance.
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The only way I see to reduce the current is to purify water… but than no electrolysis happens!
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The only way I see to reduce the current is to purify water… but than no electrolysis happens!
Even if the water if purified, the current voltage relationship will be positive linear, increasing voltage will increase current (much less current, of course because purified water has higher impedance).
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Well supposedly when resonance is reached in the cavity according to Meyer there is a kind effect on the current flow… the question is what resonance he was talking about? In that patent he talked about matching the wavelength of the movement of the ions or something very close to that…
If the resonance is in the audio range than it may not be so hard to get it ringing…
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Yes, I agree. Duty Cycle Pulses were Stan's method of controlling this sustained polarization and bursting amplitudes.
Also, most people never realize the great inhibition on tuning pulses and core saturation, that a percentage based duty cycle adjustment causes. All your signal generators are flawed, making it nearly impossible to tune replications of Stan's circuits due to all the differences in the VIC Matrix caused by parasitics and ideal vs real component behaviors.
Only having independent width and spacing control circumvents this flaw. I'm writing an article on my research on this subject that I will share sometime soon. :)
I dont know. Stan has the 7490 I.C in the circuit. this chip divides frequency and outputs a 50-50 duty cycle, so he never adjusted duty cycle in the high frequency signal, he only adjusts the gate (low freq signal) pulse and width. In the images where the primary signal is round and stretched is the result of transformer action only, not electronics.
So far, I never saw someone increasing the voltage at the cell with decreasing current at the same time. More voltage = morre current, always, thats ohms law. If you apply a HV pulse, current will flow based on the cell resistance.
The high voltage pulse is temporary. It's only there to break the water after it's already been charged by the low voltage pulses. Since the water is already near the breaking point, the high voltage pulse is just the straw to break the camel's back as it were.
This is why you can accomplish this effect even by feeding only 2V into the VIC primary.
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Well supposedly when resonance is reached in the cavity according to Meyer there is a kind effect on the current flow… the question is what resonance he was talking about? In that patent he talked about matching the wavelength of the movement of the ions or something very close to that…
If the resonance is in the audio range than it may not be so hard to get it ringing…
If we look at the flat vic core, matching the wavelenght makes more sense. The flat core VIC has aprox 750m of wire. Assuming he used quarterwave length, the fundamental freq has a 750mx4 = 3000m. 3000m is the wavelength of a 100khz signal assuming an air core. With a ferrite in the middle the inductance increases and the fundamental will lower a little bit.
Seems more plausible. I had the flat vic transformer with the identical core and windings but no sucess in achieving resonance. The only difference is that I didnt have 10 cells in series, apart from the fact that Stan probably wire the 10 VIC transformers in series to drive the 10 series tubes.
If he had 10 vic transformers in series, 100khz fundamental would drop to 10khz just like he said in his patents and yes, the transformers works in series and it is a very common stuff in some high voltage circuits like co2 laser cutter power supplies.
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I’m not totally sure if the length of the wire is so important… also this long coils resonate at much lower frequency than 100kgz from what I remember from testing..
I believe there’s a contradiction between Stan words and what was shown
Meyer talk about bifilar all the time and this Vic’s founded don’t seem to have any bifilar coil in it….
For me it’s more likely that the epg were the real used Vic than those
When applying a frequency above the self-resonant frequency of the coil supposedly than the signal is transported in the coil by capacitive effect meaning the coil kind of behave some like a capacitor above it’s resonant frequency… and what that mean?
Well it mean that when you apply a voltage to it it gets charged like a capacitor would… a simple coil would reverse its polarity immediately after it’s disconnected however a coilpacitor will be able to discharge the capacitive side of the coil first and only after that get the reversal of polarity… basically energy get consumed since the capacitance charge is opposite polarity to the inductor at the moment just where the current is interrupted…
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I’m not totally sure if the length of the wire is so important… also this long coils resonate at much lower frequency than 100kgz from what I remember from testing..
I believe there’s a contradiction between Stan words and what was shown
Meyer talk about bifilar all the time and this Vic’s founded don’t seem to have any bifilar coil in it….
For me it’s more likely that the epg were the real used Vic than those
When applying a frequency above the self-resonant frequency of the coil supposedly than the signal is transported in the coil by capacitive effect meaning the coil kind of behave some like a capacitor above it’s resonant frequency… and what that mean?
Well it mean that when you apply a voltage to it it gets charged like a capacitor would… a simple coil would reverse its polarity immediately after it’s disconnected however a coilpacitor will be able to discharge the capacitive side of the coil first and only after that get the reversal of polarity… basically energy get consumed since the capacitance charge is opposite polarity to the inductor at the moment just where the current is interrupted…
Probably not important. If I remeber correctly the 3 3000 turns coils connected in series resonate at 15-18khz with the thin vic core. With thicker cores I have it goes down to 9-10 khz.
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I’m not totally sure if the length of the wire is so important… also this long coils resonate at much lower frequency than 100kgz from what I remember from testing..
I believe there’s a contradiction between Stan words and what was shown
Meyer talk about bifilar all the time and this Vic’s founded don’t seem to have any bifilar coil in it….
For me it’s more likely that the epg were the real used Vic than those
When applying a frequency above the self-resonant frequency of the coil supposedly than the signal is transported in the coil by capacitive effect meaning the coil kind of behave some like a capacitor above it’s resonant frequency… and what that mean?
Well it mean that when you apply a voltage to it it gets charged like a capacitor would… a simple coil would reverse its polarity immediately after it’s disconnected however a coilpacitor will be able to discharge the capacitive side of the coil first and only after that get the reversal of polarity… basically energy get consumed since the capacitance charge is opposite polarity to the inductor at the moment just where the current is interrupted…
Agreed.
The capacitor's dielectric material (in this case, water) and the conductive plates will have some inherent resistance, which is often referred to as equivalent series resistance (ESR). When you take this ESR into account, the capacitor can exhibit RC-like behavior to some extent.
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Yes, I agree. Duty Cycle Pulses were Stan's method of controlling this sustained polarization and bursting amplitudes.
Also, most people never realize the great inhibition on tuning pulses and core saturation, that a percentage based duty cycle adjustment causes. All your signal generators are flawed, making it nearly impossible to tune replications of Stan's circuits due to all the differences in the VIC Matrix caused by parasitics and ideal vs real component behaviors.
Only having independent width and spacing control circumvents this flaw. I'm writing an article on my research on this subject that I will share sometime soon. :)
What you mean? With flawed signal generators? What would make it impossible to tune? To have mark space is not hard… even the pll can be made to have variable duty cycle… the fracture cell also Is some very good for the abilities
When you increase frequency (to get more pulse count), you indirectly decrease BOTH the width (ontime) and the spacing (offtime) equally.
When you adjust duty cycle % (to get more on-time) you indirectly decrease the spacing (off-time)
When you increase gate frequency to reduce pulse count, you indirectly reduce T3A (and T4A) making the gate period shorter.
Compounded by the AND gate logic required, every adjustment you make results in a tradeoff of "parameters" for the rest of the pulse, train, and gate.
What if you wanted to reduce spacing, but keep the same width? (PWM is current flow, which is directly related to managing core saturation per pulse/train)
What if you weren't bound to such shackles?
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Not to mention, dual-crossover sequenced switching that employs negative and positive elongation independently for width and spacing, and an independent offset control.
Or, how Stan simulated a biased AC wave using sequenced and random alternations swapping the B+ offtime reference during gate periods.
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I believe Meyer used this gated pulse to control… however from what I’m seeing about how the pll works and how the Q factor should be and how much it can get out of resonance all the time… summed with the patent pll info… I would say the gate must be much longer otherwise it won’t be able to lock if is to few pulses!
I believe the gate period must by at least as long as the sweep or longer
Also the sweeep should be reset by the gate somehow if used that way when the pulses start it always start from low frequency
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i got something nice for you all....
Watch this video, please
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I believe Meyer used this gated pulse to control… however from what I’m seeing about how the pll works and how the Q factor should be and how much it can get out of resonance all the time… summed with the patent pll info… I would say the gate must be much longer otherwise it won’t be able to lock if is to few pulses!
I believe the gate period must by at least as long as the sweep or longer
Also the sweeep should be reset by the gate somehow if used that way when the pulses start it always start from low frequency
The voltage across the cell should stay at least as close to electrolysis voltage at all times. The gate pulse should be set accordingly. If the gate is too wide, the charge will dip too low and then you're starting all over again without results.
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i got something nice for you all....
Watch this video, please
Very interesting… but somehow my computer downloaded a .php file i had to change to .mp4 to watch
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i got something nice for you all....
Watch this video, please
Sextuple AND gating via H11D1 (in the style of bedini 4wave)
Gate frequency is a tone as well. We are playing musical chords to the cell.
Heterodyning: Inputting 2 frequencies and manifesting 2 more. One at their Sum and one at their Difference. (3 + 9 = 6 + 12)
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Very cool sounding… I did some music connecting the pll circuit to a speaker too… sounded a bit different very playable!!!
You sound like chorus effect on guitar may mean your frequencies are not sync…
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Very cool sounding… I did some music connecting the pll circuit to a speaker too… sounded a bit different very playable!!!
You sound like chorus effect on guitar may mean your frequencies are not sync…
Yea, that's correct. Analog and antique signal generators have drift, due to aging capacitors in the timer and power supply circuits. Some fine adjustment is necessary to get them to sync.
Or perhaps, there is another benefit? That stereo/tremolo effect is wave coherence and the trading of dominance in the mix. ;)
Wave differential creates torque. Actual physical wave energy collisions occurring.