Author Topic: unipolar pulse trains  (Read 132071 times)

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Re: unipolar pulse trains
« Reply #192 on: April 08, 2009, 03:28:03 am »
alright so since the coil cost 350 from john and i want to start testing with my function generator and sweeping with the 3 inch tubes and spectrum analyzer i went out and purchased two 3 dollar mosfets IRF 523 i think..........so when the coil (hopefully) comes in tomorrow i can just jump right into testing....but for future testing i would want to get a dedicated power amplifier.


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Re: unipolar pulse trains
« Reply #193 on: April 08, 2009, 14:07:59 pm »

NOTICE HOW THE LOAD REJECTION MATCHES STANLEY MEYERS eq 6 and 7

it's just an ordinary voltage divider, that's nothing mysterious or spectacular, of course the formulas are the same :)

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Re: unipolar pulse trains
« Reply #194 on: April 08, 2009, 19:28:24 pm »
there is a reason why stanley chose that equation......load rejection is what is going on inside the water capacitor.....i have noticed that the wfc and vic coil act much like transmission lines undergoing abrupt changes.....re read 14.5.1.

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Re: unipolar pulse trains
« Reply #195 on: April 08, 2009, 20:09:52 pm »
Quote
.load rejection is what is going on inside the water capacitor

i dont think its really load rejection as much as its the mutual charge induction on the core.. they are bifilar wound.. that means you can have a positive 600 (vacuum state, missing electrons replaced with light) sitting right next to neg 600 (condensed electrons in a wire) they are magneticaly  ATTRACTED  to each other on the core.. it is more work to cross the water turbulently  then to just stay on the core.. the more wire whether it be copper or stainless is going to up voltage ability since each foot of wire is adding resistance so therefore you have a resistance to build pressure against... to call it load rejection isnt quiet tru.. what we call a load in present time deals with turbulent amp loads.. you must have some type of load if works being performed.. its a resonant load??/


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Re: unipolar pulse trains
« Reply #196 on: April 09, 2009, 16:18:27 pm »
YUP ... Its like lightning .

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Re: unipolar pulse trains
« Reply #197 on: April 10, 2009, 04:43:13 am »
i have received the vic coil from john........i blew both my mosfets in the process of trying to run amperage through it..........

tomorrow i will get a bunch of mosfets.

what i can say about johns coil so far is that all his readings are accurate....except i am getting different inductance readings with my inductance meter.........the connections are a pain in the a$s can be made incredibly easier if using a circle jumper connector.

the coil came in working beautiful condition.

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Re: unipolar pulse trains
« Reply #198 on: April 10, 2009, 10:11:16 am »
i have received the vic coil from john........i blew both my mosfets in the process of trying to run amperage through it..........

tomorrow i will get a bunch of mosfets.

what i can say about johns coil so far is that all his readings are accurate....except i am getting different inductance readings with my inductance meter.........the connections are a pain in the a$s can be made incredibly easier if using a circle jumper connector.

the coil came in working beautiful condition.

Well, i have 3 multimeters here as well. All show different readings on most of the settings.
Maybe i should buy for once a real meter in stead of all those japanese crap.....

steve

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Re: unipolar pulse trains
« Reply #199 on: April 10, 2009, 20:12:48 pm »
so here is the deal.......

i have connected the vic coil to a load...(3 inch tubes)......have connected the vic coil to my mosfet which is pulsed by my function generator at a 50 percent duty cycle.

FIRST OFF.

there is no second pulse on the off pulse.

SECOND.

Voltage is elevated and current is restricted....and i can achieve "resonant like conditions"....(meaning optimum efficiency point.)

THIRD.
but since there is no pulse on the off pulse we do not get a step charging effect inside the water capacitor nor do we achieve stanley meyers resonance.

i have replaced johns diode with 2 of my other diodes to have the same result.

and by all means the 3 inch tubes do not pull 3.3 amps. nor does it want to consume 3.3 amps.

anyone?