My new approach

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The rolled capacitor may have a high resonance frequencies and it may be behaving as a open ended transmission line in the sense that it will look like a short circuit to the input and its ends are open circuit

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The wfc is a very leaky capacitor. End of story.

I remember Stan stating that if you achieve a voltage doubling on the wfc, then you are doing as he was doing at that time.
With other words: VIC/Transformer output is 24V, then by resonance, you should measure more then 24v on the wfc.
Thats plain old school resonance. Thats the X degrees out of Phase thing.
Voltage first, then amps come.
You charge the wfc capacitor.
The power consumed are the leaky losses...
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Yes indeed!

For me it’s even simply a resistor when out of tune

The voltage across it depends on the turns ratio and coupling of the input transformer and voltage input of course

And plus’s the resonance can sum with it

I never seeing before cell resistance get higher with frequency it should be the opposite since is a capacitor

So I guess what happens is that the magnetic field makes the cell behave as a motor generator with the input dc as the power in moving


The higher speed it spin the lower the current that can goes in

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Higher frequencies need much less turns on the Vic

The Vic I designed as for 10khz 100v

Would require maybe 4 turns to work at this higher frequencies maybe less

Or would need a higher applied voltage

Pegaps now I need a even higher voltage

And maybe even more magnetic field

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On this drawings you can see what is going inside the cell according to the fields present..


There are two electric fields one being the dc one being the induction flux field in circular direction and the last is the magnetic field alternating

The dc field cause a lateral force while the induction field cause a radial force

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The wfc is a very leaky capacitor. End of story.

I remember Stan stating that if you achieve a voltage doubling on the wfc, then you are doing as he was doing at that time.
With other words: VIC/Transformer output is 24V, then by resonance, you should measure more then 24v on the wfc.
Thats plain old school resonance. Thats the X degrees out of Phase thing.
Voltage first, then amps come.
You charge the wfc capacitor.
The power consumed are the leaky losses...
You follow me here?

The water in the fuel cell is a steam bath. Corresponds to earth grounding.
Water grounding = earth grounding
Water is a source of electrons.
A capacitor cannot be a source of electrons.
The fuel cell must be made to be both a capacitor for resonance and a resistor, which in principle it already is.
The deposit on the cathode of the fuel cell (calcite layer) during training is what makes it a capacitor.

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Water become a source of electrons if the energy com from inside of it

While we are pouring energy in is actually in capacitive way

As I tried to point some time ago when water generate energy from inside the electrons come from the negative plate and so oxygen is generated ate the opposite electrode at least in theory

In one of the lectures Stan clearly stated that is all about the movement and deflection of electrons

Therefore for example we have very high ac field and we short the coil in itself at point of zero voltage the cel starts to output ac! So the cell output depend on the energy inside and how it’s going to be discharged

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Water become a source of electrons if the energy com from inside of it

- controversial statement

While we are pouring energy in is actually in capacitive way

- controversial statement

As I tried to point some time ago when water generate energy from inside the electrons come from the negative plate and so oxygen is generated ate the opposite electrode at least in theory

- you described Faraday electrolysis, not the Meyer process. Faraday electrolysis is a parasitic phenomenon that kills the Meyer process. No electrons should come out of the negative electrode

In one of the lectures Stan clearly stated that is all about the movement and deflection of electrons

- words taken out of context.

Therefore for example we have very high ac field and we short the coil in itself at point of zero voltage the cel starts to output ac! So the cell output depend on the energy inside and how it’s going to be discharged

- There is no logic here at all.
Write in the form of formula calculations.
The initial formula and how it goes through calculations and substitution into the final formula