Explain Meyers Electrons electronVolts Covalent bond theory

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Stan tried to explain us his theory about using Voltage for breaking down the water molecule.
He wanted to overcome the attraction force of the bonding electrons.
Sofar nobody really explained this to me in a normal way.
I did some research and i want to share that with you, here on our forum.

The photoelectronic spectrum of H2O reveals four different energy levels that correspond to the ionization energies of the two bonding and two nonbonding pairs of elections at 12.6eV, 14.7eV, 18.5eV, and 32.2eV.

So what does that mean now?
It means that you need somewhere between 12,6 and 32,2 volts per bonding electron.

Now it becomes massive and tricky.

If you have two electrodes and you put 12,6v, you never ever get 12,6V on 1 molecule of water.
I explain: You dont have 1 electron on that electrode. You have a lot of them. And you have to divide the applied voltage per electron going to the other electrode.
If you have two electrons moving to the other electrode, you have 6,3V per electron.

So, back to Stans theory.
He needed to to use small electrodes, which he did. He had to use high voltage (lots of electrons)
Otherwise he would not be able to do any covalent bond breaking at all.

So, now it is you turn.
If we take 1 square inch of flat electrode.
How many electrons do you have on it when you apply 20kv?

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Part2 of what Meyer explained is that when you start with putting electrical stress to a water molecule and its atoms, you stretch the atoms, for real!!!!!!
Please re read.
You stretch the atoms for a moment.
Each time you stretch or flex the atoms, they release energy. The spinning moments of all internal particles in the nucleus of the atoms are slowing down and release energy.
The equilibrium state is broken.
So what does nature do in such a situation?
It starts to compensate and energy flows into the spinning particles, so they start spin again at the same rate as before.

So, if you shoot some voltage pulses into the water, the atoms are getting charged up.

The next phase of Meyer is to pluck the electrons out of the water bath.
When some atoms are releasing electrons, it is needed to extract the electrons out of the water.
The longer the non equilibrium state, to more zero point energy floats into the atoms for compensation.


 

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try to experiment with cancelling magnetic fields of sparks not conductors because the velocity of electrons in conductors is low

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coulomb

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coulomb?

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charge on a capacitor
 
https://en.wikipedia.org/wiki/Coulomb
https://en.wikipedia.org/wiki/Coulomb%27s_law

if electrons are removed from a fixed amount of water, then there is a majority of protons left , + charge.
the Oxygen wants electrons so it has to suck them from some where

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Stan tried to explain us his theory about using Voltage for breaking down the water molecule.
He wanted to overcome the attraction force of the bonding electrons.
Sofar nobody really explained this to me in a normal way.
I did some research and i want to share that with you, here on our forum.

The photoelectronic spectrum of H2O reveals four different energy levels that correspond to the ionization energies of the two bonding and two nonbonding pairs of elections at 12.6eV, 14.7eV, 18.5eV, and 32.2eV.

So what does that mean now?
It means that you need somewhere between 12,6 and 32,2 volts per bonding electron.

Now it becomes massive and tricky.

If you have two electrodes and you put 12,6v, you never ever get 12,6V on 1 molecule of water.
I explain: You dont have 1 electron on that electrode. You have a lot of them. And you have to divide the applied voltage per electron going to the other electrode.
If you have two electrons moving to the other electrode, you have 6,3V per electron.

So, back to Stans theory.
He needed to to use small electrodes, which he did. He had to use high voltage (lots of electrons)
Otherwise he would not be able to do any covalent bond breaking at all.

So, now it is you turn.
If we take 1 square inch of flat electrode.
How many electrons do you have on it when you apply 20kv?

Thanks for posting those photo electron voltages, Steve.  I wasn't aware that Stan was into that aspect.  One value he left out is the 6.1 ev for breaking out a single Hydrogen, leaving hydroxyl.  But keep in mind that these are kinetic energy values, representing precise electron velocities to produce impact dissociation.  A cloud of electrons traveling at one of the indicated velocities will produce the desired effect when injected into some water mist.  Vibrating free electrons in a water bath, at the exact velocity to cause the molecules to split, would be a good trick, and might be a more complex approach than is needed.  This is a quantum effect - a tiny bit too much voltage, and it won't work.

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Stan tried to explain us his theory about using Voltage for breaking down the water molecule.
He wanted to overcome the attraction force of the bonding electrons.
Sofar nobody really explained this to me in a normal way.
I did some research and i want to share that with you, here on our forum.

The photoelectronic spectrum of H2O reveals four different energy levels that correspond to the ionization energies of the two bonding and two nonbonding pairs of elections at 12.6eV, 14.7eV, 18.5eV, and 32.2eV.

So what does that mean now?
It means that you need somewhere between 12,6 and 32,2 volts per bonding electron.

Now it becomes massive and tricky.

If you have two electrodes and you put 12,6v, you never ever get 12,6V on 1 molecule of water.
I explain: You dont have 1 electron on that electrode. You have a lot of them. And you have to divide the applied voltage per electron going to the other electrode.
If you have two electrons moving to the other electrode, you have 6,3V per electron.

So, back to Stans theory.
He needed to to use small electrodes, which he did. He had to use high voltage (lots of electrons)
Otherwise he would not be able to do any covalent bond breaking at all.

So, now it is you turn.
If we take 1 square inch of flat electrode.
How many electrons do you have on it when you apply 20kv?

Thanks for posting those photo electron voltages, Steve.  I wasn't aware that Stan was into that aspect.  One value he left out is the 6.1 ev for breaking out a single Hydrogen, leaving hydroxyl.  But keep in mind that these are kinetic energy values, representing precise electron velocities to produce impact dissociation.  A cloud of electrons traveling at one of the indicated velocities will produce the desired effect when injected into some water mist.  Vibrating free electrons in a water bath, at the exact velocity to cause the molecules to split, would be a good trick, and might be a more complex approach than is needed.  This is a quantum effect - a tiny bit too much voltage, and it won't work.

Thanks Tek,

Good point.
So, here is what Wiki has to say about this:
An electronvolt is the amount of kinetic energy gained or lost by a single electron accelerating from rest through an electric potential difference of one volt in vacuum.

So, if i have a potential difference of 1 volt across our waterfuelcell, electrons only flow from the cathode to the protons.
And also electrons from the water molecule flow to the anode.
The atoms feel the potential difference across a wfc.
Meaning that the higher the voltage potential across the electrodes, the more kinetec force electrons get?