The principle behind the VIC transformer

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In one patent about the pll circuit meyer describes the following

he say if the ratio of the chokes to secondary is 30:1 and 12 v is applied to the primary than the voltage is 360 v something like

i was considering my thoughts and concluded that maybe high voltage potential is the same as high magnetic field potential in essence... of course different phenomena involved,,

but i was thinking the if we want to use the coils as a dipoles how do we increase the electric field it will have?

well the answer would be more turns and a bigger thicker wire coil to get more voltage

but also the geometric arrangement of the coil must be thouht to increase its ability to work as a dipole

i believe the coils should present have a greater lengh in diameter than in width...

meaning a shorter coilwith more layers

i believe the greater is the insulation between the layers the better it will be on higher frequency...

however maybe we need it to work on lower frequency...

the higher will be the energy in the coils the higher will be the current and voltage therefore developed in the celll

meyer says the secondary must form resonant charging chokes segments...

and that at resonance the current must drop from 20ma to 1 or 2 ma


so the first thing

we need is a 40ma dc meter to connect between the secondary and the chokes segment to be able to measure it... (i tried but not with a specific meter)

another way to go is to put a resistor in series and measure on the diferential probe at the low scale... a 10ohm resistor would read 2mv at 20ma

the chokes are wound in oposite way of the secondary

the sum of choke volltages and secondary voltage must give this 20ma figure under non resonant conditions pulsing at 1khz maybe...

as the resonance is achieved the covalent switchoff will reduce the amp flow to a minimum

so lets make some math

if the cell have for sake of simplicity a conductivity of 78ohm at a certain ppm ratio

(iron present in water affect  hydrogen production)

than we know for 20ma to flow we need 1,56v to be applied on the water... if the resistance was 5000 like in my cell with very pure water it would need 100v

than if i set my transformer with maybe 20 turns at primary and i  feed with 50v i have 2,5 v per turn this is an electric field of 25mv per milimiter for a turn lenght of 10cm... so thinking about is a low electric field....

if allowing the primary to colapse to a voltage 20times greater that is possible with a high voltage igbt than it would mean an electric field of yet 500mv/mm still not seem very strong...

so how to increase this electric field?

we we need a bigger core in this case so we can get a higher flux per turn allowing a higher voltage to be applied per turn... althought it increase the turn lengh a little it will allows a higher electric field per lenght..

or maybe just air core that wont saturate allowing the current to grow according to the resistance of the primary coil

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in my quest for understanding how meyer used his coils voltage to break water without amps i found that the vic may have to have impedance match such as to transmit the power to the load at whatever frequency..

when the circuit is impedance matched the power goes all to the load... when using a TL to send power to an antena it will radiate all the power causing no reflection back in the line when the line and load have the same impedance....

if its withing the 1/4 impedance transformation mode.. than maximum power is sent to the load according to the impedance transformation equation... and its actually a resonance... but the objective being send power to the load and make this sistem such that it wont accumulate power but that it transform it by impedance transformation analogous to that of a transformer step up  or down ratio!

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impedance match for a resonating circuit would be to equal the ~XC XL AND R values..

this mean that the Q factor will also be 1 so no power is accumulated over cycles...

all power is dissipated within the load..

when we charge a coil and make it to dischage into a capacitor thru a diode the capacitor will get charged till the current in the coil vanish... the coil will be aways sending a voltage greater than the capacitor voltage to charge it untill the current is over...

this mean that at 5 khz if the capacitor have 1nf it will be an impedance of already around 40kohm... this would mean the coil to work with it and be able to dump the energy into it should at 5khz have 40kohm reactance.. this should make a 1,27H coil... but also the capacitor should have a 40kohm real resistance.. the reality is around less than that...

so the point is the amp inibither coil is wound on another core according to the techbrief...

meyer call the system unipolar... and unipolar magnetic field

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the feed back coil or any coil in the system gives a voltage signal... in the circuit,,

in my case here to capture the resonance of the coils of the vic the feedback coil is connected to another coil soo i can get the current 90 degress retarded signal..

so what if the feedback coil is not as we think it is?

meyer needed it to be coupled to another coil for it to charge to high voltage this fact anoyes me

when the transformer is in resonance this mean that the current is increased such that it accumuate energy over the cycles

there is two ways resonance can be applied in series or parallel... if in parallel at resonance the voltage is the same you apply but the input current drops as the recirculating current increase...
 
in the series case the current that recirculate is the same as applied but the voltage peaks as it is now limited to the resistance of the circuit and voltage appiled;;

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with a resonant frequency of 5khz an inductor with 700mh would give 22kohm of reactance

lets play with this value....

if we got a capacitor with 1nf and lets assume at this same frequency it will be resonant with this inductors connected to it on either side and of same size...

if we get a series resonance this mean that anothe important aspect must be know that is resistance.. so lets say we get 70  ohm at each coil..

if we want to get 1 ampere to flow we would need theoretically 140v coming from the primary to the coils at resonance for this to happen..

if 1 amper flows or recirculate there there will be formed 22kv across each coil... they can be equal and oposite or just not...

if 1 amper would flow this mean that 140w would be going on..

and this is dissipated mostly in the coils and water since water also has a resistance and is dissipating power out of the capacitance

i guess when we allow the fields to collapse by action of the diode the magic comes in

is present to you to use capacitors to restrict the current in an ac system?

for example you add a full wave bridge and two capacitors as input... it will only allow a certain current output according to the reactance... but is an isolated dc source.... but if this capacitors are in resonance this is a whole different story...

the current thru the load will depend on what?

will depend  on the resistanc of the load vs voltage input to the resonant system

because the capactors and coils if properly desined could dissipate small power..

lot of energy accumulated in the system would be present

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his device show two unterminated coils

depends where you look....