Author Topic: The VIC with resonant cavity project by Steve..  (Read 131184 times)

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Re: The VIC with resonant cavity project by Steve..
« Reply #328 on: October 30, 2016, 16:18:21 pm »
Steve and others, I am giving out a lot of information on how Stan's fuel cell works over at RWG forum You guy's may want to go check it out.

http://open-source-energy.org/?topic=2785.0

Thank you Ronny!
I appreciate your information very much.
I have also troubles to get registrated on rwg forum.
Not sure why.
Can you maybe publish some of yr content here?
Sofar, i can only read without pictures etc at rwg....

Good work my friend!
Steve

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Re: The VIC with resonant cavity project by Steve..
« Reply #329 on: October 31, 2016, 03:09:29 am »
Steve and others, I am giving out a lot of information on how Stan's fuel cell works over at RWG forum You guy's may want to go check it out.

http://open-source-energy.org/?topic=2785.0

Thank you Ronny!
I appreciate your information very much.



I have also troubles to get registrated on rwg forum.
Not sure why.
Can you maybe publish some of yr content here?
Sofar, i can only read without pictures etc at rwg....

Good work my friend!
Steve

Heres the picture Ron colored Steve. I added the  remarks 3A -3F  to it tryn to satisfy a curiosity ,not finished yet trying to show a relationship to conductivity.The second pic is a version of the original Ron colored,I haven't found the same one yet.The 3rd pic is part of where I referenced 3A-3F.
« Last Edit: October 31, 2016, 07:14:12 am by Newguy »

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Re: The VIC with resonant cavity project by Steve..
« Reply #330 on: October 31, 2016, 11:06:29 am »
A lot of people are having trouble with impedance matching. I worked out Stan's Vic for example for everyone.

Using Stan's Vic and the numbers Don gave us as and example, I will attempt to show how to impedance match it all.
Question is what is the purpose of Impedance matching?
The answer is Watts in must equal Watts out.

Let's start with the Primary, I have already show it has 10 ohms of impedance in it and how it is calculated.

Line(Primary) side=10 ohms
12volts/10ohms=1.2amps
1.2amps*12volts=14.4watts

Next we use a transformer (Amplifier) to match the Load side.
we need to know the total resistance of the load side.
Secondary side= 72.4+76.7+70.1+Re78.54+11.5=310 ohms

Now that we have a total resistance of the line side of 10ohms
and a total resistance of the load side of 310ohms

Next we take the 310ohms and 10ohms and use this formula to get the turn ratio.
Ns/Np=sqrt Zs/Zp   sqrt (310/10)=5.567
So we need a turn ratio of 5.567 to 1

We know our line voltage is 12volts We can times this by the turn ration of 5.567 which is =66.8 Load Voltage
Now we have our load voltage.
Next we calculate the load watts
using formula (66.8 ^2)/310ohms= 14.39 watts

That's how you do it

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Re: The VIC with resonant cavity project by Steve..
« Reply #331 on: November 04, 2016, 09:28:46 am »
A lot of people are having trouble with impedance matching. I worked out Stan's Vic for example for everyone.

Using Stan's Vic and the numbers Don gave us as and example, I will attempt to show how to impedance match it all.
Question is what is the purpose of Impedance matching?
The answer is Watts in must equal Watts out.

Let's start with the Primary, I have already show it has 10 ohms of impedance in it and how it is calculated.

Line(Primary) side=10 ohms
12volts/10ohms=1.2amps
1.2amps*12volts=14.4watts

Next we use a transformer (Amplifier) to match the Load side.
we need to know the total resistance of the load side.
Secondary side= 72.4+76.7+70.1+Re78.54+11.5=310 ohms

Now that we have a total resistance of the line side of 10ohms
and a total resistance of the load side of 310ohms

Next we take the 310ohms and 10ohms and use this formula to get the turn ratio.
Ns/Np=sqrt Zs/Zp   sqrt (310/10)=5.567
So we need a turn ratio of 5.567 to 1

We know our line voltage is 12volts We can times this by the turn ration of 5.567 which is =66.8 Load Voltage
Now we have our load voltage.
Next we calculate the load watts
using formula (66.8 ^2)/310ohms= 14.39 watts

That's how you do it

Dear Ronny,

Thank you for your post and Explanation.
This calculation will be handy for the persons who didnt know how to do this.

To add, i think, we should mention as well that XC and XL must match to come to these numbers of resistance.
XC and XL only match at a certain frequency. (resonance). In resonance, the fysical resistance of the coils and cell  are left over.

You also wrote on the other forum on how you start the gas production, when you have the setup complete.
I found it very interesting.
Starting the cell is like plain dc electrolysis, till water is removed and is replaced by gas.
In that state resonance seems to possible. Not in the first electrolysis state.
Can you please explain this a bit more?

Cheers!
Steve





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Re: The VIC with resonant cavity project by Steve..
« Reply #332 on: May 30, 2023, 16:45:52 pm »
Steve, As the Stans VIC can only put out 1.2Amps...
That should be more than enough to start making bubble if the vic is balances and the WFC is not electrically leaking.
So your starting out...OUT of resonance. or as Stan would say 180 deg out of phase, or dirty old electrolysis.

As your slowly making the journey getting closer to resonance for the first time, IE the cell has never been charged before above 5KV!
You will step charge your cell slowly as you keep adjusting for resonance. In turn and at the same time you do this,...your amps will go down in the mW's making more and more gas bubbles.

Think of it like push your child on a swing in the park using 1 finger!?!  How would you do it from a dead stop position to the point your child is scared of going to much higher?

Hope this helps.

Ant


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Re: The VIC with resonant cavity project by Steve..
« Reply #333 on: May 30, 2023, 19:27:15 pm »
Hi Ant,

have you been succesfull with it?

btw, nice to hear from you.  :)

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Re: The VIC with resonant cavity project by Steve..
« Reply #334 on: May 30, 2023, 21:39:37 pm »
Can anyone post a scope shot of a voltage/current waveforms, increasing the pulse voltage and decreasing pulse amps? So far, I never saw that happend, if you increase the voltage at the cell, the current will increase too. I'm not talking about RMS measurement, I'm talking about current peak measurement, and it should be measure with a non inductive resistor or shunt.

Or a scope shot with the voltage kept constant while the current increases or decreases? The cell is a resistor, you cannot apply more voltage and have less current on it, you'll always have the relationship V=R.I, more voltage = more current, always.


Thanks.

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Re: The VIC with resonant cavity project by Steve..
« Reply #335 on: May 31, 2023, 01:18:34 am »
Can anyone post a scope shot of a voltage/current waveforms, increasing the pulse voltage and decreasing pulse amps? So far, I never saw that happend, if you increase the voltage at the cell, the current will increase too. I'm not talking about RMS measurement, I'm talking about current peak measurement, and it should be measure with a non inductive resistor or shunt.

Or a scope shot with the voltage kept constant while the current increases or decreases? The cell is a resistor, you cannot apply more voltage and have less current on it, you'll always have the relationship V=R.I, more voltage = more current, always.


Thanks.

I’m working on that…

The idea I’m buying is that water must act as a kind of generator at a certain condition only…

My experience tells me that is a magnetic field plus a geometric configuration that is required to make water kind of resonate or work like a pump inside a cavity so you pulse at right frequency it must create a back emf that will show as a current reduction for same voltage apply as you pointed that it must be…

I was not considering microwaves but now it seems to me that it would be a interesting way to get voltage induced in water the problem is to rectify it and feed it back!!!

Me too never saw the effect of just water being pulsed and have any current reduction

The only way I see it was in the experiment I apply 240v with a rectifier straight to tap water and when it boils it’s current reduces some while the boil keep vigorous

The water quickly boil is very interesting but I never quantitized it very well

I remember doing it in Italy back in 2007 with 20cmx10cmx4mm electrodes spaced like 6cm apart in a 4 liter acrylic tube vessel

It consumed like 600w with Milan tap water

I didn’t even ever saw a nice 2kv wave over tap water… only very pure water was possible with those toys transformers

That’s why I designed a bigger power supply and coils to get more power maybe reach the threshold