Hey there, i'm wondering where you all got your 2.4Wh/l from.

After Faraday's law the Voltage has nothing to do with the electrolysis, i am confused a bit.

I calculated it myself after the Faraday equation,

m/M = I * t / z * F

and i get

**V***h2o2* = I * t * 1,7425 * 10^(-4) litres/Coulomb, (same parts O2 and H2, which doesn't fit really... hm)

example: 1 Amp; 1 hour (3600s)

0,6273 litres < 2/3 litres

Someone one got more information on how to calculate the efficiency? Or how do i get to 2.4 Wh/l ?

edit: I found a good site for calculcating the efficiency:

http://www.overunity.com/index.php?topic=3107.0