Katz,
It is almost impossible to make a setup with 2 tubes without the use of spacers.
As you can see on attached page, Stan was just pumping Amps into the tubes.
The only fraud thing Stan did, was that he was measuring the volts and amps on the rotor.
What he didnt publish was the volts and amps on the WFC.
As you can see, he used 500watts for powering his WFC.
Br
Steve
I dont know if it would be impossible and I also think stan meyer did not use spacers:), but if you take a look at how a tuning fork works one end will always be damped, that is the end of the tube that is connected or screwed into the mount. The bottom end will act as the node, while the top column will vibrate. Even though the pipes are fixed at one end it will not preven them from vibrating or resonating given that there are 6 tubes.
http://www.onlinetuningfork.com/http://www.stevespanglerscience.com/content/start_video/tuning-fork-demo-video?width=340&height=340Stan never mentions the use of spacers anywhere and therefore cannot be discounted.
I dont know how many of you noticed this though that stan is claiming 180% efficiency.
I have huge doubts about the figures in the page 60 pic. can some one explain how 1000 cc of gas volume is 1lb gas pressure?
using that figure the document claims his WFC gas production is @ rate of 7lbs/min or 7000 cc /min gas production.
Using that figure if we use the following efficiency calculation:
In a collected volume of HHO gas the amount of hydrogen energy will be 7744 Joules pr liter collected gas.
It is then assumed that the gas holds 20 degC and that the gas is saturated with water vapor.
Electrical energy is as known purely E (Joules) = Voltage * Amperage * electrolysis duration time
So efficiency where H2 and O2 gas is collected together is;
EFFICIENCY = 7744* V1 / (U*I*t) where
V1= Collected H2/O2 volume measured in liters
U = Electrical input voltage
I = Amperage during electrolysis
t = Time of electrolysis measured in seconds
multiply above by 100 to get % efficiency
substituting: 7744*7litres/(12.5 volts*40amps*60secs) = 1.8069 * 100
or 180% overunity
The other major doubt is, how does he get the cell to draw 40 amps without electrolyte. V = I * R and unless the resistance of the cell falls (by adding electrolyte for example) you cant really 'pump' amps into the cell.
Also he says in his video idling the dune buggy 5 volts 2 amps on the rotor. Has anyone got anywhere near as close as meyers gas production by applying only 5 volts and 2 amps on the rotor?