Hello Webmug,
1 :
When Tx1 first turn on (pulse on) the diode will be blocking the current therefore the tx5 coil send a negative voltage field to the cell in reference to ground, when the pulse terminates there is no residual energy left in the core, so the cell discharges the negative field into the ground but while doing so it act as a primary, so it induce now in the tx2 and tx4 coils thru the diode (open during pulse off) a positive field in the cell in reference to ground. The current cannot flow thru the tx5 coil cause there is already another current in it flowing in the opposite direction so the cell get charged now positively or you have now a B+ high voltage field. When 50% of the off period has passed the B-field has reached 0v and start to get positive until the point where the next pulse is applied again.
As you got initially a first negative pulse (in relation to ground) and than 180° later you got another positive pulse (in relation to ground), you clearly doubled the frequency and you got amp restricted cause the positive and negative are not being applied at the same time and also because the circuit that induces the positive restrict the ability of the positive pulse to pass current thru its source so this fact takes voltage to the upper limits cause impedance is maximum.
The secondary is being feed magnetically by a resonant tank and is connected in series with contrary polarity so the current cannot flow. Actually it can and it does but is only ma to charge up the cell as a whole.
So tx5 is tuned it resonates acts as a secondary during pulse on and primary during pulse off,
The tx2 coil and tx4 act also as secondary but during the pulse off, when the capacitor reaches 0v it start acting as a primary together with tx1 to induce in the tx5 coil the negative pulse once again during pulse on.
Is it clear to you? .
2
I think that the circuit is tuned to electrical resonance but at a certain high voltage field level water breaks down. The wave form will be exact what stan showed across the cell.
The tx5 coil signal should be ac so as tx3 at resonance. At resonance as the fields will be completely out of phase 0 current should flow thru the electrodes,thus become only static electric fields. However some losses must occur and as we are doing it dc the resonance must satisfy to restrict the amps to certain degree as to be able to maintain a dc offset. Is like the voltage between the plates never get 0 during the pulsing operations.
My best guess is that we can do take the resonant frequency of the water like stan describe and design the electrical resonance in accordance with the frequency and impedance requirements but initially I believe we should go for a 5 to 10khz electrical resonance and than try to detect the water resonant frequency when the resonant action inside the cell takes place to trigger it only need the high voltage. Something tells me that maybe this resonant action is what need the amps to be restricted too...well i don't know...
Stephen meyer showed something like the resonance frequency was 500 Hz and the water resonance seemed to be 14khz... however if you analyze his graphics he had the unipolar pulse happening but the resonance occurs pulse yes pulse no. Than in the other graph he shows the fields in the water. This was sure for tap water.
Again stan talked about secondary to charging choke ratio, and I think that here lies the deal.
If you take the primary to secondary ratio, it is not important cause it does not even have anything to do with the secondary.
we must follow this path
TX1 ___>TX5____>TX2 ->| Tx4
1° we need to determine tx1 to tx5 ratio. This will be the increasing step voltage per pulse. But initially we should think about current!
I guess if we start from 12v 5 amps
If we have a 1:5 ratio being tx1:tx5 we should have 60 volts induced in the tx5 coil and a maximum of 1 amp can flow thru it.
Now we take this 60v and 1 amp. Under resonance the only parameter that will hold will be the impedance, the voltage will not be 60v under resonance but much higher cause the current will be 90° away from current and so voltage will be the product of the recirculating amperage times the reactance, so lets say if you have say 10kohm reactance and 1 amp flowing you will get 10kv across the coil, so the secondary will receive an ever increasing voltage according to the amount of energy accumulated in the tank. Actually the secondary if is even bigger than the tx5 coil an even higher voltage will be applied during pulse off. Basically as the diode implies that tx4 and tx5 become a current source if the current is restricted the voltage goes to infinity. This is certainly the deal.
If the resonance is too damped you need to get more voltage in the tx5 coil from the primary
