Author Topic: WFC VIC  (Read 290035 times)

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Re: WFC VIC
« Reply #160 on: February 28, 2011, 17:35:15 pm »
@Dynodon:
Actually, if, as you said, the chokes are connected with different potential to the cell, there is IMHO only one possible way of wiring. You said, all coils do have the same orientation. But I'm not sure, if we mean the same. Here an example from a patent:
(http://img14.imageshack.us/img14/3482/patviccircuitwobsmall.jpg)
Is this the way, the 5-VIC-Coil was  wired? As you can see all coils are wound counter-clockwise. And are then connected "in series". Now the question to Don (and only to him): According to your understanding, are the coils in the pic all connected with the same orientation or not?
I would be really grateful for an answer. As the correct wiring is certainly the most important factor, for a replication.
Additional question: The side, where the diode was, was connected to which tube of the WFC. The outer or the inner? Could you see that on the originals?


Edit:
Addtion: I always see new pics pop up every now and then. Don't you wanna make a DVD with all the pics you made of Stans stuff together with the videos made (in good quality) and sell it? I for sure would  buy it.
« Last Edit: February 28, 2011, 18:45:10 pm by Kali_ma_Amar »

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Re: WFC VIC
« Reply #161 on: February 28, 2011, 17:46:58 pm »
I think the inner tube must be the resonant one.


Kalli where did you took this fig from?

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Re: WFC VIC
« Reply #162 on: February 28, 2011, 18:11:51 pm »
This is the only pic in which the current from secondary to chokes are countered by induced emf in the 2 chokes, induced by the primary's magnetic field.
In other pics this only happens on the second negative resonant choke.

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Re: WFC VIC
« Reply #163 on: February 28, 2011, 20:39:08 pm »
BIG SMILE!



If the 8xA is connected as I think, then the "Amp inhibiting effect" is very strong. 10 volts as circuit input voltage, the coils resonating at +/- 5 volts (not much I know, but limited by the input voltage), but now ask me, what the measured DC input current was after the diode...5uA??!!??yes 5 Microampères not Milliampères. As soon as my usual meter just displayed 0.0mA I looked for my special one which measures only from 0 to 100uA. And then I adjusted the frequency until I just got down to 5uA. Then my idea was immediately:
There must be some AC capacitively fed in over the diode, otherwise I just cannot explain this. I mounted a shunt resistor in between. First very low ohmic...nothing...then I increased until I could see some very short millivolt peaks with a 1kOhm shunt. And the measured voltage and the picture actually shows no capacitive feed. It also shows such a low DC current and no AC!!??!!



I've already seen a lot, but from a pure electrical engineer point of view, I just cannot explain this!!??!! What's going on. I just cannot believe, that the losses in the core are that small (but it's the only explanation), so what's going on? But still the bigger question I have is: What the he** is actually resonating here???
Actually I'm currently really speechless and this doesn't happen often to me ;D ;D

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Re: WFC VIC
« Reply #164 on: February 28, 2011, 22:15:23 pm »
I experimented with the 8xa last summer, videos on youtube, and will be doing so again in the future, now I have a scope and some more ideas, Kali, would you like to get yourself a projects section and share a few things about your 8xa? I'd like to learn from your experiences here too

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Re: WFC VIC
« Reply #165 on: March 01, 2011, 00:17:18 am »
@Kali
Do you think the reason for the low current measure is because you haven't reached the threshold voltage or current to turn the SCR on?

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Re: WFC VIC
« Reply #166 on: March 01, 2011, 03:24:55 am »
hello kali, if you make a simple diagram of what you are doing i could try help understand what is happening.. from your description i don't know exactly what are you measuring or doing...

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Re: WFC VIC
« Reply #167 on: March 01, 2011, 10:23:30 am »
@Tony: With my current experiments I currently don't use the SCR switching logic, I feed directly the waveform from a FG. So I'm testing just Stan's "Amp Inhibiting circuit".


As I again thought about the whole thing, I realized, that the only explanation is really, that the core losses are that low, which really is strange to me. But what's even stranger is the  fact, that although the coils resonate at AC with the WFC in between, the WFC has only DC on it. IMHO this can only be explained by the huge capacity (supercapacitor) of the WFC compared to the small distributed capacity.
IMCHO (in my current humble opinion) I think that there are only 2 wirings which would make sense. One is a tank circuit with only the second choke (both chokes same polarity to the cell), the other is both coils just resonating in unisono together (different polarity to the cell). And especially for the second variant I would be very very interested on Don's answer on my question a page ago about the orientation. I would be really grateful to you Don, if you can answer this question.


EDIT:
While biking I realized why I needed just such a low current. Not because the loss percentage was so low, but because the oscillating energy is so low. The capacities are so small, that there's almost no energy oscillating. Therefore the needed input power is extremely low. This actually explains why Stan could us a core with such a small core area without saturating it. Although the energy say at 1000 volts will be 10'000 times more, it is still small, as the expected needed input current with the same oscillator would be then around 50mA.
« Last Edit: March 01, 2011, 16:33:46 pm by Kali_ma_Amar »