102 plates drycell

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@Keith
The endplates have an extra extension on who i can hookup my power. Because they are on the inside, you dont see them (well)
A toptank will indead do the job .. :-)

@ Brian
Thanks dude. I must dissapoint you here. This new cell is using KOH, otherwise i never get over 100% Faraday.  However, the cell can also run on tapwater only.

@Fabio
No pump is needed, because of the way its build. Also, the reservoir has lower wateroutlets then gasinputs.
The cell is designed for around max 11 amps. Its normal operation should be a on 8/9 amps. 2kW consumed power when driven on 200V by 10 Amp is the goal.

The facts on missing electrons in outer orbits of atoms was already know by me. Thats exactly the reason why i used negative charge on my airprocessor.
Just like Stan said. Try to stop the re-combining of hydrogen with oxygen. And it works, as i already told you :-)
Maybe we will get the burn, but no water. So what happen to the hydrogen atom?.....no idea, to be honest.


Steve

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Hi steve

i was guessing that both ways could work on avoiding the reformation, but while ionizing negatively we can fill 1 or both of the electron holes doubling the number of water molecules forming OH using more oxygen than the original from electrolysis or actually even preventing the reformation in the case we fill both holes, but if we thus ionize positively what would happen is that we could open one more holes in the oxygen atoms allowing it to bound with 3 hydrogens forming H3O witch would be actually avoid the reformation of water molecules as stan described, because for every oxygen there will be 3 hydrogens!!!

This would lead us to have the following:
For every 3 mole of water reacted or 54 grams we would have 2H3O so we are losing 1 oxygen or 16 grams. Thus we would have 38 grams in the end. 70% of the original mass

The negative way lead us to have the following:
For every 3 moles of water reacted or 54 grams we would have 6OH thus having 3 more oxygens creating water ending up with 102 grams. Almost doubling the mass!!! 188% gain in mass

I'm not sure which would work the better! Or witch would gain more energy... but steve now that you have lot of gas you can perform some tests. Try to use more than one stage being one negative other positive and so one. the last one will give you the reversed polarity you want in the end if i'm not wrong. (i read about in some patents about ion generation)

I was thinking that maybe is possible to charge the all engine! to prevent the gas from discharge... .

This would explain the noize recorded in the stan demo video

Thus we can use:

Laser energy to help the atom to get exited
High voltage
Magnetism
Electromagnetism

And we have :

Movement of the air 

Think about steve 

Best Regards

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Hi steve

i was guessing that both ways could work on avoiding the reformation, but while ionizing negatively we can fill 1 or both of the electron holes doubling the number of water molecules forming OH using more oxygen than the original from electrolysis or actually even preventing the reformation in the case we fill both holes, but if we thus ionize positively what would happen is that we could open one more holes in the oxygen atoms allowing it to bound with 3 hydrogens forming H3O witch would be actually avoid the reformation of water molecules as stan described, because for every oxygen there will be 3 hydrogens!!!

This would lead us to have the following:
For every 3 mole of water reacted or 54 grams we would have 2H3O so we are losing 1 oxygen or 16 grams. Thus we would have 38 grams in the end. 70% of the original mass

The negative way lead us to have the following:
For every 3 moles of water reacted or 54 grams we would have 6OH thus having 3 more oxygens creating water ending up with 102 grams. Almost doubling the mass!!! 188% gain in mass

I'm not sure which would work the better! Or witch would gain more energy... but steve now that you have lot of gas you can perform some tests. Try to use more than one stage being one negative other positive and so one. the last one will give you the reversed polarity you want in the end if i'm not wrong. (i read about in some patents about ion generation)

I was thinking that maybe is possible to charge the all engine! to prevent the gas from discharge... .

This would explain the noize recorded in the stan demo video

Thus we can use:

Laser energy to help the atom to get exited
High voltage
Magnetism
Electromagnetism

And we have :

Movement of the air 

Think about steve 

Best Regards

I tested with positive ionization of air and that didnt do anything.
The only thing i could try is to feed the HHO and air thru the ionizer, but my theory is that is doesnt make any sense and is dangerous.
HHO is already ionized when it leaves the wfc.

Steve

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Hi steve

Did you tried to ionize positive or negatively only the air or exhaust that were entering the engine???

Regards

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Hi steve

Did you tried to ionize positive or negatively only the air or exhaust that were entering the engine???

Regards

only the air.....

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Small update:

Just finisched building my powersupply for the new drycell.
I ran a powertest and it works like it should.

Also got my waterreservoir annex bubler. This one is made of SS and has 2 wateroutlets and 2 gasinputs, conform by new drycell.

My wife complains about the fact me not being available last days.....
Well. I am at home, but most of the time in my lab..hehehehehe

Anyway, it all looks great and is almost ready for a first testrun.
Sadly for this, it has to wait for a week.....
I am out  fisching for a couple of days.
The good news is that the paint can dry up nicely now....

Cu

Steve

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Here an update on my current build.
I had made a nice SS bubler annex reservoir for the 2 sections of wfc.
Sadly this concept didnt work. Current started to leak between the 2 sections thru the waterhoses!!!!

So, i build me 2 seperate bublers.
Here are the results from my first testrun with KOH.
This is the water that is cleaning the cell, so to speak.
Hopefully i will get more KOH for a new load of water.

102 plates and 101 cells.
At 185V by 6A its doing a 1.5 ltr HHO per 12 seconds (7.5ltr/minute)  = 95% Faraday = 6.8mmw  (1.83V per cell)
At 191V by 10A its doing a 1.5 ltr HHO per 7 seconds (13 litres/minute) = 95% Faraday = 6.7mmw (1.89V per cell)

These are not bad numbers. When the cell get more hours on running and with new water, it hopefully will do a bit better.......Target is 100%.

My setup seems to be able to do like 15 litres HHO within reasons.


Steve

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...These are not bad numbers. When the cell get more hours on running and with new water, it hopefully will do a bit better.......Target is 100%...

Very nice Steve!

Now use hot water and a COPPER intercooler (Nickel even better) to go over 100%