### Author Topic: New VIC pictures discussion!!!  (Read 42383 times)

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##### Re: New VIC pictures discussion!!!
« Reply #48 on: February 11, 2009, 03:50:20 am »
The 430 FR SS wire that Dankie had made was 19.775 ohms per ft.  to get the 11.6K ohms requires 586.6 ft.  the blueprints of Dyno's coil in metric are :

Choke mean dia. = 11.4649 cm
Primary mean dia. = 12.1503 cm
Secondary mean dia.=18.9421 cm

I used the Where statment from the brief to get the #s above

(L) is the inductance in microhenries, (N) is the number of turns, (A) is the mean radius in
inches, (B) is the length of the coil in inches, (C) is the depth of the coil in inches.

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##### Re: New VIC pictures discussion!!!
« Reply #49 on: February 11, 2009, 04:50:41 am »
so wait from my understanding the choke radius is....approximately 4.5 inches in diameter?...the photos of dynodon holding it do not look 4.5 inches......

NOW EVERYTHING CALCULATED HERE IS IN INCHES.

anyways with the numbers you have given me....we would have to wind the ss wire for each choke approximately [(N) 496.4 turns]....another thing is how is the length of the coil (B) different for every coil?? they should all be the same....i am going to use the information from the file you emailed me .....the outer which is (2.875)-(.238)-(.415)= 2.222 and the inner which is (2.875)-2(.238)=2.399 and the average of both of those would be [2.3105 (B)]

the depth for the inner would be 1.625-1.250= .375 while the depth of the outer would be 2.750-2= .75 and the average of those would be [(C) .5625]....now this depth is correct if we fill each cavity to the brim and each and every cavity if just plained filled.

the mean radius would be the inner plus the outer.....2/2=1 1.25/2=.625....625+1=1.625......1.625/2=  [.8125 (A)]

now another thing is for the N factor...i'm not sure if i would multiply this by two since it is for each inductor or leave it alone......for this i will use it as it is.
so from that we plug it into our equation to yield.

L = 4158.46 microHenries

and now we can calculate the capcitance at our chosen frequency to give us 40,000 volts......because if we were to add  a water capacitor with a higher capacitative reactance (Xc) than our VIC's inductive reactance (Xl) this coil would produce jackshit.....be sure to check out my calculations i have posted under my project section.....so everyone can understand how to calculate there desired frequency for there setup.

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##### Re: New VIC pictures discussion!!!
« Reply #50 on: February 11, 2009, 05:20:52 am »
oh one more thing when you do the math on the specs for water consumption per second at 65mph you get 92.85 miles per gallon......which i might say is very impressive.

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##### Re: New VIC pictures discussion!!!
« Reply #51 on: February 11, 2009, 05:52:42 am »
Kinsis,

My mistake it was the mean circ. not dia.  (dia. x Pi)

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##### Re: New VIC pictures discussion!!!
« Reply #52 on: February 11, 2009, 06:22:24 am »
Kinesis,

I did give you the correct radius in the #s for the (Eq 20)  With the wire I got from dankie with the Choke mean circ of 4.51375" and the ohm of 11.6k it would be  11,600 / 19.775 x 12 / 4.51375 / 14 segments = wraps per segment x 2 for biflar  = 222.6 rounded up to 224 wraps per seg. x 14

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##### Re: New VIC pictures discussion!!!
« Reply #53 on: February 11, 2009, 06:45:09 am »
alright so all we have to do is replace the "N" factor with the proper amount of winds.....but not right now....i'll do it tomorrow....and tomorrow we will figure out the capacitance and the length of the electrode that is needed for this vic coil with out side being .75 wall being .0625 and inside being .5.......we can calculate all of this just from knowing the inductance of the VIC and our input power......hopefully things match up well.

Here is the equation for capacitance of a cylindrical capacitor......

L is the length
a is the inner diameter
b is the outer diameter (remember to minus the wall size .0625)
E sub 0 is E node which is our permittivity constant of 8.85 x 10^-12 farads/m or the permittivity of water which i don't know.
C is our capacitance

C = 2*pi*E0*( L / (ln (b/a)) )

hopefully tomorrow reveals some interesting results in calculations....but i need sleep.
« Last Edit: February 12, 2009, 07:35:55 am by kinesisfilms »

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##### Re: New VIC pictures discussion!!!
« Reply #54 on: February 11, 2009, 14:04:31 pm »
This coil assy contains three bobbin areas in relationship to the core.

Two sets of 14 ea individual spiral-wrap coils electrically connected in sequential order.

There is inductance coupling of (511a xxx 511n) and (512a xxx 512n)

I am lost and have no understanding of how to do this math.

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##### Re: New VIC pictures discussion!!!
« Reply #55 on: February 11, 2009, 20:06:39 pm »
yeah the all in one vic is a tad to agressive.....this is why i bought a spectrum analyzer......i can just sweep to its exact point without the need for math....

plus i use a completely seperate primary and secondary.

so all my math falls down to the bifilar inductor and water capacitor.

now for the "N" factor which states "number of wraps or turns" does this mean number of turns for the primary and secondary along with the chokes or just the wraps of the bifilar chokes???.....very vague here.....i would take it since we are looking at the vic coil as one coil then the correct N would be the amount of wraps for the primary+secondary+chokes.......so once again for clarification......for chokes i would be using 224 x14 to get 3136 total for the bifilar chokes?...and for the primary i would be using 382 wraps? and for the secondary i would be using 273 x 14 = 3822.....if these are correct i will proceed with finding the inductance......also when i go to calculate the proper wfc size for this vic i will be choosing 10khz since it is reoccuring frequency in his writings, but if you have a frequency in mind i will try multiple ones.