If I remember well the relative dielectric constant is determined as the ratio between applied voltage and the induced contrary voltage inside the capacitor and is measured by charging the capacitor and subsequently disconnecting it from the source while still measuring the voltage across the capacitor.

From the document i attached there is an example for the hydrochloric acid which has a dielectric constant of 4.12 acording to the reference...

In the example is not really clear, because they say E0=1,5v and Enet=1,15v being Enet=E0-E1 solving E1 becomes 0.35v

Than they say that K=V0/V

however 1,5/1,15=1,3 and the value i found for hydrochloric acid dielectric at the reference is 4,12

so i found that 1,5-1,15=0,35 that would be the E1 the induced contrary voltage than if i divide 1,5/0,35 than i find a value that is in agreement with the reference 4,3.

this would lead to

For example you charge a water capacitor to 100v And its dielectric constant is 81k Thus the induced contrary voltage equals 100v/81k=1,234v So if a capacitor was charged up to 100v and is disconnected the measured voltage is 100v-1,23v=98,76v

If the document was right:

If it was like they say in the document the calculation for water would be 100v/81=1,23v however this time the 1,23v is the remained Enet so the E1 would be 98,76v

If it were vacuum which has 1 as dielectric constant, the induced contrary voltage should be zero than i would guess, so 100/1=100 so Enet=100 and thereto E1 polarization = 0. Which seems to be the case...

So why the contradiction on the hydrochloric acid? is the document wrong only there?

reference:

http://www.asiinstr.com/technical/Dielectric%20Constants.htm#Section%20H