 Author Topic: My Thoughts on how Meyer split water  (Read 53058 times)

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« Reply #88 on: July 30, 2011, 12:36:32 pm »
Getting back to the 12th root of 2 ratio, ... do you guys know that in music the 12th root of 2 ratio is exactly the difference between two notes! E.g., an A has a frequency of 440Hz, the next higher note is the Ais which is 466.16 Hz, the difference between that is exactly the 12th root of 2 or 1,05946309. This is the same for all subsequent notes. So does this mean that it has to do something with the sound wave created in the cavity as well?

Sharky Login to see usernames Re: My Thoughts on how Meyer split water
« Reply #89 on: July 30, 2011, 17:12:38 pm »
Getting back to the 12th root of 2 ratio, ... do you guys know that in music the 12th root of 2 ratio is exactly the difference between two notes! E.g., an A has a frequency of 440Hz, the next higher note is the Ais which is 466.16 Hz, the difference between that is exactly the 12th root of 2 or 1,05946309. This is the same for all subsequent notes. So does this mean that it has to do something with the sound wave created in the cavity as well?

Sharky
It all has to do with sound waves "vibrations" in the cavity.

Check attachment "Music of the Molecule" pdf

Br,
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« Reply #90 on: July 30, 2011, 18:54:18 pm »
Yea Puharich gives these overtones and such.

(http://www.globalkast.com/images/tonywoodside/ap_freq_diagram1.GIF)

(http://www.globalkast.com/images/tonywoodside/AP_Overtones.PNG) Login to see usernames Re: My Thoughts on how Meyer split water
« Reply #91 on: July 30, 2011, 19:52:12 pm »
(http://www.globalkast.com/images/tonywoodside/AP_Overtones.PNG)
I'm not a musician so my knowledge is limited.

Notice the frequency's in the Octave (ratio 2:1) from 360Hz (D = 360Hz) (+deltaOmega)
360.00 x (12th root of 2) = 381.40Hz (384Hz)
381.40 x (12th root of 2) = 404.08Hz (400Hz) (E = 405Hz)
404.08 x (12th root of 2) = 428.11Hz (432Hz)
428.11 x (12th root of 2) = 453.57Hz (450Hz)
453.57 x (12th root of 2) = 480.54Hz (480Hz) (G = 480Hz)
480.54 x (12th root of 2) = 509.11Hz
509.11 x (12th root of 2) = 539.39Hz (540Hz) (A = 540Hz)
539.39 x (12th root of 2) = 571.46Hz (576Hz)
571.46 x (12th root of 2) = 605.44Hz (600Hz) (f0=600Hz=Omega.r
605.44 x (12th root of 2) = 641.44Hz (648Hz) (C = 640Hz)
641.44 x (12th root of 2) = 679.58Hz (675Hz)
679.58 x (12th root of 2) = 720.00Hz (720Hz) (D = 720Hz) (-deltaOmega)

Keely mentions a so called "pitch" between two oscillating Atoms. The pitch is the vibration of frequency between them.
The oscillations of an atom has a very high frequency, but the "pitch" frequency is very low (differences between them).
If we vibrate (give impulses) on that frequency we can change the oscillation of the Atom and make it unstable.

Br,
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« Reply #92 on: July 31, 2011, 17:58:57 pm »
According to Don's messurement, the electrode distance is 2,413 (or 0.095") mm for the latest cell. Frequensy responce is 3610.5263Hz (3,61kHz) at that distance - to match the 3.98kHz from Puharich, we need the electrode distance to be 0.086" or 2.1844 mm electrode distance.

An electrode distance of 1.5 mm or 0.059 inch equals 5813.5593Hz (5.81kHz) Login to see usernames Re: My Thoughts on how Meyer split water
« Reply #93 on: July 31, 2011, 18:05:04 pm »
According to Don's messurement, the electrode distance is 2,413 (or 0.095") mm for the latest cell. Frequensy responce is 3610.5263Hz (3,61kHz) at that distance - to match the 3.98kHz from Puharich, we need the electrode distance to be 0.086" or 2.1844 mm electrode distance.
How did you calculate this, can you elaborate? Isn't that water-gap in the GHz frequency range?
Also the value of 0.090" showed up in the patents.

Br,
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« Reply #94 on: July 31, 2011, 18:09:11 pm »
Quote
How did you calculate this, can you elaborate? Isn't that water-gap in the GHz frequency range?
Also the value of 0.090" showed up in the patents.

Br,
Webmug

You can go to this site or do it manually. http://www.sengpielaudio.com/calculator-wavelength.htm

0.090" = 3811.1Hz Login to see usernames

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« Reply #95 on: July 31, 2011, 18:12:54 pm »
I will see if I can change the speed of sound to match that in water