Gimmick

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For the circuit simulator:

$ 1 5.0E-6 10.20027730826997 50 5.0 50
g 208 304 208 352 0
w 208 208 272 208 0
d 272 208 320 208 1 0.805904783
R 208 144 208 96 0 0 40.0 20.0 0.0 0.0 0.5
w 208 144 208 208 0
l 320 208 400 208 0 0.0026 0.0
c 400 208 400 288 0 1.59E-10 386084.34048985044
w 208 272 400 288 0
s 208 304 208 272 0 0 false
w 400 208 480 208 0
w 400 288 480 288 0
s 480 288 480 208 0 1 false
o 6 64 0 35 655360.0 12.8 0 -1

close and open the switch parallel to the cap several times

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You gave me a good idea

$ 1 5.0E-6 0.04345982085070782 49 5.0 50
g 176 320 176 368 0
w 176 224 240 224 0
d 240 224 288 224 1 0.805904783
R 176 160 176 112 0 0 40.0 14.0 0.0 0.0 0.5
w 176 160 176 224 0
l 288 224 368 224 0 0.0010 0.0133020921358354
w 176 288 368 304 0
s 176 320 176 288 0 0 false
s 448 304 448 224 0 1 false
c 368 224 368 304 0 1.0E-10 13.302100541494601
w 368 224 400 224 0
w 400 224 448 224 0
w 368 304 400 304 0
w 400 304 448 304 0
r 400 224 400 304 0 1000.0
w 176 160 192 176 0
w 224 208 288 224 0
o 9 64 0 35 160.0 0.00625 0 -1

Think of the resistance as the resistance of the water and the up side of the capacitor as one of the two tubes and the other side the other tube. Instead of having a spark on the switch it will happen inside the water i guess. the bigger the resistance the better thus i guess distilled water would be better for this what do you think?
Capacitance will be very small and the inductor can have up to 1 ohm to limit the amperage to about 10 amps a high amperage relay could be used...

Thanks

Regards
Sebos

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voltage jump on switch off, bemf forced to resonate? what are you thinking haithar?

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Hi donald,

When current flows thru the inductor it start storing energy (if air coil will store and store and store because will not saturate) but when the switch open it will collapse the field and discharge all the energy accumulated in the magnetic field all in once inside the capacitor thus it would start to oscillate back and forth. As the energy in the inductor can accumulate in relation to only its resistance i mean if the inductor have 1 ohm of ohmic resistance and 12volts are applied 12 amps would flow thus this 12 amps * its reactance at the resonant frequency, and you can calculate this knowing the capacitance, will be the reached voltage peak. being a resistor in parallel would only matter for the Q factor but the peak voltage would be as much as high because a capacitance is the same as a shot circuit, more than an inductor.   

I think this is a very good idea and is quite the same what steve proposed in his NEw DC Resonant charging circuit ...   

I just think that we must find a two way for the resonance to oscillate in a dc  manner, i'm starting to think that thats what stan did with the so called bifilar coil. however i still don't know...

Regards
Good night my friends
all the best for you all

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I think this is a very good idea and is quite the same what steve proposed in his NEw DC Resonant charging circuit ...   

Yes and i was quite surprised to get unlimited voltage in the simulator if you close the switch for unlimited time and then open it. I'm pretty sure this won't happen in a real circuit so i posted this as a gimmick.