Author Topic: Stanley Meyer, how his schematic works  (Read 504 times)

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Stanley Meyer, how his schematic works
« on: November 12, 2018, 11:23:03 am »
I will break the basic effect down in terms I hope everyone can understand. The resonant charging choke does not utilize EM induction(ie.. a magnetic field) it utilizes electrostatic induction(the electric field) like a capacitor.
If you take a balloon and rub it in your hair the balloon becomes electrostatically charged through friction. If you bring another balloon near the original one there will be an attractive force between the two because the charged balloon induces an opposite charge in the approaching balloon. The laws of electrostatic induction state the originally charged balloon will NOT lose charge but will charge the other balloon in an opposite sense---google electrostatic induction for yourself if you don't believe this. We can say the two balloons are now a capacitor---two oppositely charged objects(conductors) with a dielectric between them (air). There is also an issue of "net" charge whereby electrons must move to the approaching balloon from a source but that is not an issue here.
There is no difference between the balloons and metal conductors such as copper wires the only thing that matters in surface area. The two separated balloons form a capacitor, two metal plates can form a capacitor or two copper wires separated by a dielectric(the insulation). Physics states one object can charge another in an opposite sense and the object inducing the charge will not lose charge thus it has lost no energy. Read whatever you wish into this, It is a scientific fact and I did not make this up for your benefit.
The main problem is that nobody other than Tesla has bothered to understand what might happen if a very high voltage(electrostatic) short duration pulse were applied to two conductors separated (a capacitor) by there insulation( the dielectric). Also what happens when the two plates are connected in series? Potential moves on the surface of the conductors before one milliamp of current moves so there is an instant when the two separated conductors wound one the same core have a huge potential difference between them. One conductor has a surface charge in motion but the next winding ahead of it has yet to be charged thus an opposite charge is induced in it creating a potential difference, when the circuit voltage drops this inter-winding capacitance is discharged as an electric current. But the current is a product of electrostatic induction not a changing magnetic field as in EM induction. In which case--- the source of the charge(the line voltage)inducing an opposite charge in the secondary windings can lose no energy in the process" as physics states. Only extremely short duration/high voltage pulses manifest this effect, such as high frequency square waves at high voltage which is exactly what Meyer's was using in his working circuit.

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Re: Stanley Meyer, how his schematic works
« Reply #1 on: November 12, 2018, 11:26:49 am »

Maybe it's time for a lesson in basic electronics:D The only problem with Meyer's technology is that nobody has a clue as to what he was doing in his circuit, so let's walk through it. In the circuit below we have a pulsed DC current input to a toroidal core transformer, the secondaries of this transformer form a resonant series circuit. The resonant series "working circuit" consisting of the secondary transformer windings, blocking diode, a resonant charging choke,water cell capacitor and variable inductor. When people look at this circuit they see what they want to see, that is what there textbooks have told them they should see, but that is not all there is. So let's see what really happens based on facts I have learned from actually building the circuit.
First a DC pulse charges the toroidal transformer primary inducing a higher potential voltage in the transformer secondaries. Since the primary current is pulsed DC the secondary current is also pulsed DC, the secondary windings produce a current flow through the blocking diode then when the primary current is abruptly stopped an inductive discharge (flyback current) is discharged through the blocking diode from the secondaries. Many people consider the inductive discharge and other reactive components as having no power in them but this is only because they lack the understanding of how these reactive components should be utilized. The inductive discharge would normally fly right through this circuit with little effect if it not for one component ---the resonant charging choke. I wonder why it is named resonant "charging" choke? this would imply it is charged by something and it is charged by the inductive discharge from the transformer secondaries. The resonant charging choke is Tesla patent 512340 "coil for electromagnets" and is a bifiliar wound coil. This coil does one thing-----it stores the high voltage inductive discharge from the transformer secondaries as capacitance between the conductor windings and this capacitance also cancels the inductance of the coil. This is one point many people cannot seem to understand, If the capacitance of this coil constitutes energy stored in the form of an electrostatic field then this capacitance must discharge when the circuit potential drops but the capacitance is not polarized externally:eek: ----so where does it discharge to?. The blocking diode ensures the resonant charging choke current discharges in the same direction as the current that charged it in the first place. So here we have a situation where the induced current in the secondaries charges the resonant charging choke and the water cell capacitor, next the resonant charging choke discharges with an equal current in the same direction through the water cell capacitor. The resonant charging choke bifiliar would coil is an integral part of what Tesla refered to as a "magnifying effect" whereby the potential of the circuit does as much "work" as the current. Next we have a variable inductor after the water cell, this variable inductance is designed to tune the circuit. A variable inductor stores energy in the form of a magnetic field, this inductance can act just like a flywheel. That is the inductance will oppose a rising current by producing a magnetic field and it will oppose a falling current by raising its voltage to maintain current----just like a flywheel uses momentum to resist change. That is the purpose of the variable inductance---to maintain current flow in one direction through the circuit which includes the water cell capacitor. I hope you are starting to see what is happening in this circuit, there is no overunity---that is impossible, there is no magical zero point energy appearing out of nowhere, there are no fairies sprinkling magical pixie dust to power the circuit. There are know and proven facts, action and reaction, in this case the facts are that the inductive discharge current from the transformer secondaries has never been utilized in an efficient manner. Each DC input pulse will raise both circuit potential and current simultaneously, as such the energy or "work" performed in the working circuit will always be greater than the input energy.
It is said that the definition of insanity is doing the same thing over and over again and expecting different results. So why do you do the same things over and over, building your circuits in exactly the same way, it should be obvious you will never achieve different nor better results.

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Re: Stanley Meyer, how his schematic works
« Reply #2 on: November 13, 2018, 20:52:22 pm »
Hello Steve.

It is clear on the Independent Test Evaluation Report that it is not overunity, nor even 100% efficient.

The supposed gain as Stan claims was from resonant cavity but nobody saw any demonstration.

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Re: Stanley Meyer, how his schematic works
« Reply #3 on: November 14, 2018, 02:41:28 am »
Has anybody got any info on the effect with different guage of electrodes?
I think Stan demonstrated ther are no adverse effects on them ,so how thin are they suppose to be with the voltage thats required?

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Re: Stanley Meyer, how his schematic works
« Reply #4 on: November 14, 2018, 08:15:39 am »
I only can say that the thicker the metal, the less resistance?
But from Stan files, i cannot remember him mentioning anything like that except that he was clear and happy to see how many electrons copperwire contains...

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Re: Stanley Meyer, how his schematic works
« Reply #5 on: November 14, 2018, 08:20:18 am »
Hello Steve.

It is clear on the Independent Test Evaluation Report that it is not overunity, nor even 100% efficient.

The supposed gain as Stan claims was from resonant cavity but nobody saw any demonstration.

That was a test with a tubecell driven by an alternator electromotor setup.
Thats not OU at all from an electricity perspective.
If he had the bif coil in there and he would have hit the water with hv spikes, then he might have createe a different isotope of hydrogen with more mol mass.
Then the ou numbers would be different......

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Stanley Meyer: the real deal
« Reply #6 on: November 17, 2018, 18:26:17 pm »
$ 1 0.000005 10.20027730826997 50 5 50
T 208 192 320 144 0 0.01 1 0.10025545798798863 -1.714352890758164e-7 0.999
v 304 304 208 304 0 0 40 5 0 0 0.5
w 208 304 208 192 0
f 320 80 320 128 40 1.5 0.02
w 304 128 208 128 0
w 208 128 208 144 0
w 336 128 368 128 0
d 208 128 208 64 2 default
c 208 64 368 64 0 1e-8 3270.171199719963
w 352 144 352 80 0
w 352 80 368 80 0
w 368 64 368 80 0
w 368 128 368 192 0
w 368 192 368 304 0
w 304 304 368 304 0
R 320 80 400 32 0 2 400 5 0 0 0.5
w 352 144 352 192 0
w 320 192 352 192 0
w 320 144 368 128 0
o 8 64 0 4099 5120 0.05 0 2 8 3
o 1 64 0 4099 5 0.8 1 2 1 3

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Stanley meyers real deal
« Reply #7 on: November 17, 2018, 18:30:26 pm »
Its working in my simulator now.
It has been so obvious and i never seen it.
Stanley's schematic is a boost converter and he doesnt use a resistor between his capacitor and " ground" but a coil...
One side of a bifilar coil. Or a transformer like an audio transformer....Didnt he say that?
In his car he had to use his battery as basis.
Boost up the voltage in a controlled way. The waterfuel cell gets highly conductive when current flows and then the boost circuit doesnt work anymore.
So he had to add somekind of resistance between the cell and ground.....

Do you see it?