Stan Meyer says you have to ask the right question. So let's determine how much gas is produced by the vertical cluster array tube in

the various demonstrations.

The approach is to determine the amount of hho gas needed to cause a specific change in pressure. The moving pressure gauge is seen in

the videos, so possibly by seeing a change in pressure in a closed vessel, the amount of hho gas needed to cause such a changem ight be able

to be calculated.

Step 1

What is the volume of air in the vertical cluster array tube above the water level.?

By looking at the available images, there's a couple parts to the calculation:

1. The volume of air in a cylinder portion of the volume

2. The volume of air in the cone shaped portion of the volume

3. The volume of the air in the pipes to the pressure gauge

The sum of the above volumes should represent the volume of gas above the water level

Formula for volume of cylinder Volume (v) = area base(b) times

Height (h)

So now to get some measurements

1.What is the inside diameter of vertical cluster array demonstration tube?

Dynodon had some information on this (See attachment)

Inside diameter of demo cell = 4.75 inches

The area of the base is 1/2 D squared. Times pi

therefore:

The base of the cylinder of gas is 2.75 squared times pi = 23.76 square inches.

This is the of the base of the cylinder that will be used in the calculations.

------------

It struck me that the height of the cylinder that we are calculating is very small

perhaps only a few inches. SO A SMALL AMOUNT OF GAS WOULD CAUSE A

LARGE INCREASE IN PRESSURE, If the volume of the air was lets say a gallon

the same amount of HHO introduced would cause a much smaller increase in

pressure. So if one wanted to show a high pressure of HHO the amount of air above

the column of water can be made small

It also occurred to me that if the pressure increased to 15 psi which is about 1 atm 14.7 lbs per square inch

a double amount of air would double the pressure

If air was being introduced and the pressure doubled in one minute then the volume of air

being introduced/ minute would equal the volume of air that was in the vessel to begin with

so lets say for example it taes 15 seconds to go from 0 to 15 psi , then4 times the volume of

air in the cell initially if being produced so if we can determine the time to reach 14,7 pounds

then that is the amount of air produced

If Stan flushed the cell of air by leaving the gas valve open at the start of HHO gas production and then subsequently shut it, then the math is

considerably simplified. If the volume of space above the water level is determined and if we assume standard 14,7 pounds per square inch

then how long does it take to go from 0 psi to 14.7, then the volume of HHO that is produced in that amount of time is equal to the

volume that is equal to the space above the water

so no lets go back to the video in the environmental tape and dealership tapes that have views of the gauge see how long it takes to produce a given increase in pressure

pounds/square inch The application of Boyle's Law would indicate that a doubling of the pressure with a constant volume means that twice the mass

of gas in the same volume will double the pressure. So if we go from 1 ATM to 2 ATM the amount of HHO produced means that a vooumme of hho equal to the void was produced

1 Dealership Tape

Pressure in psi

11 to 14.75

time elapsed in sec

35 sec

3.75 change in psi / sec = .1071

therefore 14.7 / .1071 = 137 sec/??

to generate gas to fill void ?

2 Environmental Tape full

ok so let compare that to the environmental tape gasproduction rate rate

Pressure psi time in sec

For an estimate of the height a comparison between

Diameter and the distance from the water to the

Bottom of the conical cavity should suffice

Several frames of the video were selected to compare the height of the air column

from top surface of the water to the bottom of the conical top cap

Then volume of air in the cyclinder part of the cavity

Is calculable

The estimate the volume of the air in the conical

Portion of the cavity requires another formula

Formula for.volune of cone

V=. Pi times r squared times(. H divided by 3)

Now in this case the base of the cone is a little smaller

And a different height needs to. Be determined

Lastly the volume of gas up until the shutoff valve needs to determined

Once the three major volumes are calculated they are totaled and converted to liters

This represents the volume of the air cavity above the water

The temperature of the air is assumed to be 70 degrees Fahrenheit

Air pressure is. Assumed to be. 1 ATM Standard.