Thats 7.2 % effecient.

This from the how stan powered his altnerator page: [page 8]

In a collected volume of HHO gas the amount of hydrogen energy will be 7744 Joules pr liter collected gas.

Electrical energy is as known purely E (Joules) = Voltage * Amperage * electrolysis duration time

So efficiency where H2 and O2 gas is collected together is;

EFFICIENCY = 7744* V1 / (U*I*t) where

V1= Collected H2/O2 volume measured in liters

U = Electrical input voltage

I = Amperage during electrolysis

t = Time of electrolysis measured in seconds

multiply above by 100 to get % efficiency in terms of input joules output joules

substituting: 7744* 0.5 litres / (25 volts*35amps*60secs) = .0737

or 7.37% percent efficient in terms of energy conversion.

This will be the exact same output of regular straight DC electrolysis without electrolyte.

I am sure the True efficiency will be even lower if you calculate the input not as 875 watts output by the alternator but the watts consumed by the drive motor.

Stan got 180% overunity using the same formula for the figures he provided in page 60 of his international testing data document. 7000cc or 7 liters per minute 500 watts.

Long ways to go hydro to achieve any effieciency remotely close to stans efficecncy.

do you have any thoughts on this:

The guy in this video has on clue about hho but this video is on the overunity forum and the waterfuel forum.