Author Topic: the dielectric property of water  (Read 10236 times)

0 Members and 5 Guests are viewing this topic.

Offline Login to see usernames

  • Global Moderator
  • Hero member
  • ****
  • Posts: 3607
Re: the dielectric property of water
« Reply #24 on: May 26, 2010, 05:11:52 am »
today I was thinking that meyer didn't generated too much hydrogen.
I was thinking about the numbers meyer gave to us and was relating it to cold fusion. 

I think that he was transforming the neutron on the deuteron percentage in the water into helium and energy by creating a fusion reaction. I think that this is why he didn't reused the water.

I think that he created a plasma (hard X rays) and ionized positively the oxygen atoms up to the point where it has got up to the threshold where the forces of attraction between oxygen and hydrogen is stronger than forces between the protons to start the chain reaction where the neutron of the deuteron is released and collide with other molecules of water causing instant explosion or detonation. _I think that he did it very precisely and controlled, and very concentrated in a very small amount of water.

His exhaust maybe was helium and h3o+ or h4o+ maybe thats why he said it need to be reenergized. Actually maybe it need photons and more oxygen to stabilize and become water again. ...

Offline Login to see usernames

  • Member
  • **
  • Posts: 106
Re: the dielectric property of water
« Reply #25 on: May 26, 2010, 06:54:18 am »
ok i am going to chime in here since you all seem to be dancing along my notes. but first some facts from common science.
Dielectrical breakdown of water happens at approx 70Mv/m (thats 70 mega volts per metre) That is the voltage required for "water" to conduct. Scale this down and its about 70Kv per mm.
If you look at my project you will see that there is a phenomenon known as the avalanche effect (i'm pretty sure i put it in there :P). One of the few known processes of overunity. This has only been noticed on the nano level and is hard to consistantly replicate.
Dielectric avalanche happens at about 30% over the dielectric breakdown point of a substance. <note at this point the 100kv supply in my project>.

Other observations and readings that could be implemented sideways to help, Electric fields (these are produced by voltages, *WINK*, *WINK*) can accellerate/excite the electrons around them. Point in theory - if you could stablize an electric field at just under (or maybe over) that of the avalanche point of water this would excite/accelerate all of the loose electrons and those in the molecules them selves, to do most of the work for you.
Introducing a flood of "loose" and charged electrons (laser maybe) to the effected area would be like "multi-ball" in a pinball game.
Draw backs, your electrodes loose their charge with the transfer of energy (in other words the "loose" electrons rob you of your field very fast), every tried to generate 100kv from 12v. Its not that easy or safe.

Possible thoughts to help - PVC coating on electrodes. By increasing the gap to 150% (the voltage also) you can cover the plates in a 0.25mm thick coat of PVC which has a much higher breakdown voltage (400MV/m i do believe)

Please remember that the "conductive" voltage of water is the point when electricity will flow through the "substance" (hence why adding a nice electrolyte lowers that voltage). And breakdown voltage is the point where the non-conductive part breaks down and conducts.

This has (to me) explained a lot about the misconceptions in the way Stan Meyers describes what he is doing (please note these are my own interpretations of what has been said and i am not saying that they are right). Voltage doing the work - ie the electric fields produced by high voltages. Why it doesn't matter what sort of water you use. Why, how and process for the modifications to the alternator and the explanation with the small voltage increases to get more. etc etc

I'll leave it there before i create more of a wall, If you want me to elaborate on anything please don't fill this post unless it is relevant, just link either into my project area where i am happy to answer question or start a new thread :)
« Last Edit: May 31, 2010, 07:38:18 am by CrazyEwok »