Author Topic: Start here your topics on the water injector & ambient airgasprocessor system  (Read 35485 times)

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Steve,
you're the only one who replied. I probably have not been clear. you do not have to extract electrons from water but the water itself as a dielectric creates free electrons inside when electrically charged. The phenomenon is called dielectric absorption but you need an water bi-distilled for obtain best results and right PH. The second is the correct circuit (positive on outer tube) so it is clear that the first circuit included within the patent has been manipulated.

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    • water structure and science
Steve,
you're the only one who replied. I probably have not been clear. you do not have to extract electrons from water but the water itself as a dielectric creates free electrons when electrically charged. The phenomenon is called dielectric absorption but you need an water bi-distilled for obtain best results and right PH. The second is the correct circuit (positive on outer tube) so it is clear that the first circuit included within the patent has been manipulated.

Thank you for sharing this, but what is then left over to know?
Are you suggesting that we should use salt as catalist?
And what about the driving circuit with the famous chokes?

Steve

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HI Steve,
you have the solution right before your eyes. You need to use salt only if you use RF inside the cell. You do not need even a catalyst, you have enough extra electrons when the brown gas dissociates to liberate hydrogen and oxygen. you just need to figure out what is the dielectric absorption, and that kind of power supply you must use. For this you get to study but not for a long time to fully understand how it works. with respect to water is essential that both bi-distilled and has a pH less than 7 for properly ammonia creation. About chokes..  these can be eliminated for the moment, I don't use these..
« Last Edit: October 11, 2011, 02:15:54 am by tutanka »

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NITROGEN/WATER GAS REACTION INSIDE UV REACTOR
 
SEE DIAGRAM ATTACHED

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Interesting! I appreciate, your theory. Is clear you are working hard and seriously in it. For me the explanation why you get more power than you put in is because is a catalyzed reaction, (maybe almost spontaneous) so you probably just photoactiwate it...


Makes lot of sense to me.



I'm studying chemistry of radiation, and i'm learning about fotochemistry... 


After all if i understood well, you are dissociating and later combusting the N2 with the OH to form N20 and free up H atoms that subsequently joins with N and form amonia or hydrazine...


Well since water always keeps self-ionizing itself, you get a bunch of oh atoms all the time...


This agree with the fact that you mean acid water goes better for amonia than for hydrazine...   


Maybe you dissociate the N2 in a hot arc, and probably thats why you want pure N2. Otherwise you would get it oxidized which is useless for your reaction.


What intrigue me now is what you mean by "You do not need even a catalyst, you have enough extra electrons when the brown gas dissociates to liberate hydrogen and oxygen. you just need to figure out what is the dielectric absorption, and that kind of power supply you must use."


What you mean by extra electrons?


Did you tried diffusion electrodes?

What you mean here? "You need to use salt only if you use RF inside the cell." Kanzius?


Best Regards
Fabio

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HI Fabio,
First of all thanks for write here.
About your question Im happy to reply to you.
1- Water PH is very important in that process, for obtain NH3 you need PH <7.
2- You don't need arcs, plasma or some energy lost in heat for ionize nitrogen.. in that thread initially I have been write about that.. nitrogen in fact is ionized from the same water gas directly passing trough the same UV field. You need an "connection" from water gas and nitrogen or reaction can't appear.. you can ionize nitrogen in other stage but the time of ionization is very slow , another method is pre-charge nitrogen as Meyer using gas processor.
3- About catalyst .. Surely you know how catalyst work.. that is need for add ions or electrons inside reactions.. brown gas is special water gas and the extra electrons are inside molecule. When molecule split or burn released these, in our case are used for new molecule formation, instead when brown gas burn the extra electrons are used for fuse metals, vaporize metals or weld metal or other material together. Only the extra electrons are responsible for that.
4- About new cell.. In patent of Meyer some informations are wrong, some are reported on other patents for protection but all is written.. I suggest you to download meyer memo pdf file and watch the diagrams inside. Surely your eyes will notice the differences and your mind will analyze it in real time.
5- If you use RF you must use salt yes.. only 1% inside that but why you want complicate your life? 
I suggest you follow the road to produce brown gas in quantities reading and looking at the diagrams carefully meyermemo pdf file within the page 84
Other suggestion.. the liquid water that you put inside cell must be pre-charged first , remember pre-charged as Meyer suggest not pre-ionized  ;)
 
Regards
Alessandro
 
 
 
« Last Edit: October 11, 2011, 19:16:57 pm by tutanka »

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Images extracted from meyermemo pdf for to help your mind to quickly understand

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sebosfato wrote:
Interesting! I appreciate, your theory. Is clear you are working hard and seriously in it. For me the explanation why you get more power than you put in is because is a catalyzed reaction, (maybe almost spontaneous) so you probably just photoactiwate it...
Yes! your concept is right, photoactivation is the key (in that case) .. when molecules of water are extremely reactive as brown gas you don't need more energy for split these but only right level of energy in that case right wavelenghts for ionization and dissociation
« Last Edit: October 12, 2011, 17:06:41 pm by tutanka »