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Stanley Meyer => General Stan Meyer topics => Topic started by: Steve on September 05, 2016, 10:22:07 am

Title: VIC = Balun?
Post by: Login to see usernames on September 05, 2016, 10:22:07 am
Hi ,

Again some possible theorys on how the VIC is build and how it is supposed to work.
Its about the 2 chokes.
Would it be possible that they must act as an antenna balun?

Please read the links. I read many similaritys.

cheers

http://www.antenna-theory.com/definitions/balun.php

http://ham.stackexchange.com/questions/538/using-a-balun-with-a-resonant-dipole

Title: Re: VIC = Balun?
Post by: Login to see usernames on September 05, 2016, 10:36:32 am
I would focus on the current baluns...

This would mean that we should measure currents on our scope and not voltage waveforms.
Maybe thats why nobody have been succesfull in replicating Meyer.

Title: Re: VIC = Balun?
Post by: Login to see usernames on September 07, 2016, 07:46:27 am
Hi Steve,

You may have hit on something when you said the word balun.  But what if it's the exciter array itself which is acting as a balun?  The way he has the sets of coaxial tubes connected in series, with two 90 degree bends in each of the jumper wires.  Each jumper is a half turn inductance.  If it was strictly to add the resistance values, a straight diagonal wire would work.
Title: Re: VIC = Balun?
Post by: Login to see usernames on September 07, 2016, 22:14:08 pm
Looking at how the wires are connected to the tubes....it looks like they are the same polarity or at the very least ,the outer tube of one tube set is the same polarity of the inner tube of the adjacent tube set.
I haven't seen anybody talk about the function of having the tubes wired that way but it looks like they are effectively wired for the same polarity In some way.
Title: Re: VIC = Balun?
Post by: Login to see usernames on September 07, 2016, 22:41:42 pm
Looking at how the wires are connected to the tubes....it looks like they are the same polarity or at the very least ,the outer tube of one tube set is the same polarity of the inner tube of the adjacent tube set.
I haven't seen anybody talk about the function of having the tubes wired that way but it looks like they are effectively wired for the same polarity In some way.

I've been thinking about the possibility of free electron build up on one of the electrodes, relative to the other.    Cross wiring them like seen in his pictures would prevent sparking through the water, in a given tube set.  But the inductive bends in the jumpers could cause the array to act as a pulse forming network.  This might be important for balancing the impedance to an input PFN.

Here's an example of the type of balun I was remembering:

(https://s20.postimg.org/5n4wwfay5/balun2_1.gif)

Maybe a little far fetched, without a top connection except through the water.

I just started a new project involving a hidden wire inside the inner tube.  A pure static charge on this wire would place the same static polarity on the outside of each electrode tube.  But the inside surface of the outer tube would be the opposite polarity.  This, in itself, will polarize the water, and also present the sparking hazzard.
Title: Re: VIC = Balun?
Post by: Login to see usernames on September 08, 2016, 05:53:06 am
I've wanted to go back and look at the reference with the 3rd ring electrode at the top of one drawing. ..the most I can remember was it dealt with the EEC .
Title: Re: VIC = Balun?
Post by: Login to see usernames on September 09, 2016, 00:12:19 am
I've wanted to go back and look at the reference with the 3rd ring electrode at the top of one drawing. ..the most I can remember was it dealt with the EEC .


In a soup consisting of water molecules, gas ions, and free electrons, a water molecule which becomes ionized by losing an electron will typically recapture the same, or different electron in 180 micro seconds.  (Just under two tenths mili second.)  This is in the absence of an external field which pulls the free electrons out of the mix.  And this recapturing is also prevalent with gas ions in the EEC which are non polarized and therefor bouncing around, rather than being stretched while held stationary.  A third electrode - connected to a charge pump circuit - can remove enough free electrons to allow the gas ions to remain ionized and become even more ionized by gaining energy through impact with other molecules.  I see no reason why a third electrode wouldn't also aid the water splitting process.  Pulse mode water splitting exceeds the maximun efficiency for Faraday type electrolysis by quite a bit.  As a result, the charge on the positive electrode can only neutralize a small percent of the free electrons given off by the water during a given pulse train.  For the best possible operation, the rest of the liberated electrons also need to be pulled out of the water.

Instinctively, Meyer's system should produce far more gas than shown.  It's quite possible something's missing from his schematics, whether he included that third electrode in his Exciter Array or not.  This is where a little experimenting is needed, to tell the tale. 
Title: Re: VIC = Balun?
Post by: Login to see usernames on September 10, 2016, 20:57:52 pm
I think the part of it dealing with  "tuning in with voltage " plays a significant part ....(the repelling (ionization)part).Is it the electron or proton requires 13ev charge to eliminate the attraction force holding them together? Can't proof read my posts from my fone but u get wat I mean.
Title: Re: VIC = Balun?
Post by: Login to see usernames on September 10, 2016, 22:21:10 pm
I think the part of it dealing with  "tuning in with voltage " plays a significant part ....(the repelling (ionization)part).Is it the electron or proton requires 13ev charge to eliminate the attraction force holding them together? Can't proof read my posts from my fone but u get wat I mean.

That's the electron.  A singly ionized water molecule retains both protons, through valance electron sharing.  But I thought I read somewhere that it's 16.9 ev?
Title: Re: VIC = Balun?
Post by: Login to see usernames on September 11, 2016, 01:47:27 am
I remember in the textbooks they say 13.6eV but Steve Meyers said it was actually more like 11 to pull the electron out but...wat actually happens is it gains a repelling force great enough to separate them to a certain distance.
Electrons of course have the same charge but at rest so to speak the repelling force isn't strong enough to seperate them to an antibonding distance untill it reaches 13 or 11 eV....I think that's how I'm seeing it.
Title: Re: VIC = Balun?
Post by: Login to see usernames on September 14, 2016, 17:54:21 pm
13 eV as far as i remember. But what does that mean in normal life?

Back to my balun topic:
primary characteristics of baluns: causing currents to be equal in magnitude and out of phase.
In Meyer language translated: the two chokes on 1 core must put out equal current and voltage towards the electrodes?
Only then, we might see the Meyer miracle?


cheers