Well it might seems strange, i made an excel sheet and ploted a graph, at resonace of course the reactances are the same and thats why current is maximum, however the XC is not linear like the inductive reactance, so at resonance both are the same but as the frequency is increased the higher is the XL and the XC becomes lower as the voltages should be equal to the reactance times the current, the voltages across the inductor and the capacitor become smaller but the capacitance voltage drops more than the inductor.

Also the lower is the Q factor the greater is the difference in frequency between the maximum voltage at the inductor and at the capacitor accoring to the graphs... Actually when i learned about the harmonic oscillator at the physics lecture, i learned there are two types of resonance, one is at the amplitude and the other is at the power. Maybe thats the difference...

Yet I attributed the lower voltage at the capacitor than at the inductor to the fact that although the capacitor holds the charge, it also has the greater loss in the circuit. so or the capacitance change as a function of V(t) and i think it does because i got to change the frequency to find a greater voltage if i raised the Vt applied.

Again at F=0 the capacitor has Vt the inductor has 0v

Closer to resonance the capacitor has greater voltage than the inductor, the current start to raise

At resonance the voltages should be equal but as there are losses in the capacitor it will have a lower voltage than at the inductor. current is maximum

little above the resonance the inductor voltage still greater than the capacitors, the current decreases

way above resonance the voltage at the inductor Vt and capacitor is 0 the current is 0 too

In theory this should be the behavior

In the case of water I think because of the losses, the voltage across it aways decrease from 0 frequency to max frequency. so no voltage peaks... Maybe at resonance it decrease less..

Thats why i said its easier to find the resonance measuring the voltage across the inductor...

Since stanley had the feed back on the inductor, this imply Zero current switch and imply that the frequency is adjusted to max inductor voltages.

Ts as i stated @resonance XL = XC so XL-XC=0 condition required for resonance, yes there is a bandwidth not much wide.

What i'm saying is the waters capacitance is not the calculated value because it's a lossy dielectric, this experiment thus allow you to empirically determine the capacitance observing the frequency where resonance happens.

The first graph has 100 ohm resistance and the other 20 ohms

C = 500n

L = 1mh

Fres=7118