function of VIC: rethinking signals...

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actually this question is to get dynodons response:

is it possible that the secondary was less turns than the primary?

Steve meyer says in a radio interview that it only takes 11 volts to pull an electron from hydrogen.

if the primary has 60 volts at 600 turns, and the secondary has 20 volts at 200 turns, then 1 amp at the primary should equal 10 amps at the secondary

now with such a strong 20 volt signal and such a high amperage on the secondary, the magnetic flux is greatly increased in the core and the amp restriction is very high in the chokes at resonance...with the 20 volts passing through to the wfc waveguide..and a very high magnetic field at the chokes... a very strong opposition to current flow past the chokes...

thinking outside the box... were the drawings misleading?

i really dont think so, but its worth a try.
any comments from others ?

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Good questions again.

I suggest you read up on Rutherford–Bohr. Losing electrons happens by use of adding energy.
Normally, that would be photonic energy and you measure that in eV like with LEDS.
The ground state energy level of the electron in a hydrogen atom is −13.6 eV
Hydrogen's ionisation energy is 1312 kJ mol-1
I am pretty sure that Steve Meyer ment this and not normal 11V stuff......

http://en.wikipedia.org/wiki/Bohr_model

http://en.wikipedia.org/wiki/Hydrogen

http://www.chemguide.co.uk/atoms/properties/hspectrum.html

Steve

 

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Ali,as you can clearly see in the pictures of the coil packs,the secondary coil is alot larger than the primary.It is also evident in the readings taken of the coils as well.All of the coils were traced out to their connections.
Don

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@All

Hey guys 

@Ali

The main point at Stans 3-23 was that he was using relatively small AWG 29 copper wire.
AWG 29 = no more than 0.5-2 amps... My primary AWG 22 heats up a lot from 2 amps so AWG 29 should pass even less...

"Stanley:  ....so voltage can take over and perform in dead short conditions...."  How can voltage can perform in dead short conditions - wich is what we get in water capacitor - almost dead short. Then how can voltage perform in dead short with no amps... should be dissipated immediately in other words overhelmed by the losses if you will.  Mystery to me.

Minde

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What if one of the tubes were insulated? By some kind of surface oxidization or other materials. In this way we really have a water capacitor, but we need strong electrostatic field between the tubes, this means high voltage, to can pull away the molecule.