Water purity: drinkable, from kitchen sink to cell. No smell of chlorine in the water, City water, processed.
Cell spacing is 1/8th inch.
For you 3.175 mm spacing.
130 volts / 3.175 mm = 40.945 volts / mm
At this spacing the cell is drawing 5.8 amps.
You suggest 50,000 volts / mm
Lets assume the water resistance remains constant at 33.3 ohms (which by my current tests it does not)
The voltage of 158,750 volts (50 kv * 3.175) needs to be applied to get the 50 kv / mm.
158,750 volts / 33.3 ohms = 4,767 amps.
I really didn't want to buy a power plant for this experiment.
How am I to get mili amps across the cell and keep the voltage high? When the high Voltage pulse hits the water, 159 kv, it will NEVER rise above the losses in the ampdraw. This high voltage at mili amps will read at the cell about 10 volts.
If I applied 158,750 volts to the cell at 5.85 amps I would read 120 volts across the cell.
You are saying I can produce 120 cc of gas with a larger spacing in the same time? I have 4 tubes I will connect to each outside tube with 3/4 to 5/8 inch spacing. Be right back with that experiment.