A new idea for the approach of the alternator concept

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In Steves post above,he said a man he knows felt the wires going to the cell were warm.The 40 amps is in that line going to the cell.Each tubes is consuming @4.4 amps each.The voltage to the amature is only around 5 volts.
It's all in the report,and we've been over this before somewhere in this site.
Don

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Oh ok, i see where your going with it now.
Some other input,  Stan also says on video when running the car at idle 5 volts it is 2 amps 10 watts..

In a normal transformer your output would be equivalent to the input in watts if there isnt a loss in the transformer.. So one would say in standard equation watts divided by amps to find the volts of the output if it known to be 40amps.. A standard transformer would be 10/40=.25volts, thios would be a step down transformer we know stan stepped up.. We know that this doesn't hold true in this application since the transformer is not a standard application. It is a generator and has a rotation variable to be equated as well..

Some notes i want to make from Stan's video of the first run... The hose leaving the fuel cell is going to the silver box on the car.. To me this say there must be a ionization process going on in that box before going to the intake.. the hose may just be wrapped around that box to hold the hose in the intake but i wouldn't be surprised  if it is being put into a higher state of energy in that silver box..

also notice the pully ratio Stan has going to the alternator.. seems like one are 3 inches in diameter.. this tells me Stans looking for a stronger torque from the electric motor and less rpm..

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In the alternator set up,you are inputting 10 watts into the armature,but you have 1100 watts of electric motor turning the alternator.So the 40 amps going to the cell is generated by the electric motor rated at @ 1100 watts.You need to count the motor watts also in the whole picture.
Don

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yes but the motor was running from 110v no?


I'm here studying a resonant tank like i did in the past and the dissipation of the components...


I'm planing to use 110v straight to the transformer but every time i plug it still explodes the mosfets diodes...  in simulation there are max about 500watts going.


I'm running out of money and don't know if i will keep burning components...


I tried adding a capacitor in series and also a lamp but then the power get too limited.


Any idea how to stop burning?


 

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ok thanks for clearing up for me.. so the value of the rotation is determined by the wattage of the motor turning it..

Can we say 1100 watts and 10 watts doesnt apply any gain just the generated field to move charge in the stator based on rotation? we still use 1110 watts but only 1100 is seeing the cell.

1100/40= 27.5 volts @ 4.4amps

I see it being a 27.5 to all tubes since i think its determined by the wiring arrangment of series or parallel for the tubes.. Stan wires in parallel in all the stuff i have read..
we can conclude that the water fuel cell non isolated water capacitor is using right under 4.4 amps per fuel cell.. How does the water stay cool? is it something to do with the ratio of volts to amps?  or does water only reach a certain degree determind by the amplitude of amps?

If stan were to raise voltage to up production this is done by applying a higher voltage to the rotor? or speeding the rotor up? or? lol

i just did some math.. if we were to up voltage in the rotor one would think it will create a stronger field in the stator and create more amps plus voltage

well lets say we did this and raised amps from 40- 50

1100/50 = 22volts
a 5.5 volt decrease and a jump in amps to 5.5

if we were to lower the rotor field to push 30 amps you get

1100/30= 36.6volts and 3.33amps.

so what i think about this is you can lower a stator field but so far until it is not even noticed by the stator..

the only alternative is a step up coil with taps that you can switch between different taps to allow a varied voltage level??