voltage performs work..
if we were to want to know the resistance of water to voltage we would need to know its dielectric properties.. (conductivity) stan says rain water is around 78.54 ohms a millimeter i suppose.. lets say this it true.. then we could say a cell with 3mm gap is 78.54 x 3 = 235.62 ohms for a water cell with 3mm gap contain rain water?..
so how many amps will water take on per volt?
i think thats the real question we dont conceive properly.. to induce a field in a space will change the timeshare rate of electron in a direction providing amps.. the real question is what is the linear gain in amps to presence of voltage field that has a sharp rise time.. here is the answer to the problem... we know how many electrons pass one point in a given second..
well what is the distance traveled of them electrons in one second?.. one amp crossing the cell how long did it take a electrons to get to the other side? how ever long that was i would consider it the initial acceleration of the pulse input for a givin voltage from there on would be amps in circuit i would think id circuit remain on..
voltage turns off to prevent current..and the field collapses providing back emf to swing electrons back towards negative so them electrons are swinging back into balance naturally (universal energy) and then they are hit with another pulse.. (50 percent duty cycle) higher voltage higher frequency because the charge traveling from point A to point B is speeding up (raising in amps) in order to know the proper frequency we need to know the speed of charge at the a given voltage which can be provided by knowing the dielectic properties of a substance (resistance of water)
here is the grand finnally my friends
to understand where the energy is it is in amps.. steve is right i think..
he may of not used amps in the circut but he "perpetuated" amps in water.. not only perpetuated but maintained polarity taking away the main cause of heat which is caused by the switching of the polarty of the di pole 180 in and out rapidly.. "exactly what the steam resonator is doing"..
now i am going to go over how you find out the proptional gain of amps in water per given volt.
first you need to know the dielectic value of water which is 78.54 ohms a millimeter.. (not sure of stans units)
then you need to know your capacitor gap.. example is 3 millimeter
78.54 x 3mm= 235.62ohms for a 3mm gap
heres what i have been missing and i think most everyone else has too
http://en.wikipedia.org/wiki/Siemens_%28unit%29 the conductance of water is calculated like this
the units for conductance (the opposite of resistance) are called siemens
G= conductance
G= 1/R =I/V
what does this mean?
for the example 235.62 it would be like this
1/235.62 = .004244122
conductance is also referd to as siemens
all in all if water is 235.62 ohms then it will have a gain of .004244122 amps per volt.. you could convert this my 10 to negative 6 power
4244 microsimens
now lets talk high voltage..
2kv
2000 x .004244122= 8.488243 amps
the key is understanding there is a peak inertia traveling across the cell for a specific amplitude then i think it drops at impact (connection of transmission in electric perspective i think).. if you cut off power right before at impact of peak amps on the other side of the cell they will be rejected by the back emf in the other direction most importantly it wouls have experienced a jolt of 8 amps ..
resonant frequency changes with amplitude.. i dont completely understand what im speaking of yet..
all in all by knowing the conductance per giving volt you may determine how long it takes for amplitude to cross the cell providing you with a frequency known as resonance.
this is what i see dont know if im right but i sure do feel as if it is correct..